Biochemistry (Looseleaf)
9th Edition
ISBN: 9781319114800
Author: BERG
Publisher: MAC HIGHER
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Chapter 30, Problem 7P
Interpretation Introduction
Interpretation:
The effect of a mutation that avoids the σ subunit from separating from the RNA polymerase core should be determined.
Concept introduction:
Non-competitive inhibition can be defined as a type of enzyme inhibition. In this inhibition, usually, the inhibitor diminishes the enzyme activity. The inhibitor gets fixed like the normal substrate does to the enzyme. It occurs even if it has been previously bound or not to the substrate. Unlike competitive inhibition, non-competitive inhibition cannot be overcome with the additional substrate.
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Students have asked these similar questions
Complements. The sequence of part of an mRNA is
5'-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3'
5'-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3'
What is the sequence of the DNA coding strand? Of the DNA template
strand?
Transcription. Using strand 1 of the DNA molecule as a template, transcribe a messenger RNA molecule (a.k.a. mRNA transcript).
Strand 1
3’ End
TTG
CTT
CAC
CTT
GCG
CGC
CCG
CGC
TAA
TTG
5’ end
mRNA
An extra piece. In one type of mutation leading to a form of
thalassemia, the mutation of a single base (G to A) generates a new 3'
3' splice site (blue in the illustration below) akin to the normal one
(yellow) but farther upstream.
Normal 3' end
of intron
5' CCTATTGGTCTATTITCCACCCITAGGCTGCTG 3'
5' CCTATTAGTCTAIIIICCACCCTTAGGCTGCTG 3'
What is the amino acid sequence of the extra segment of protein
synthesized in a thalassemic patient having a mutation leading to
aberrant splicing? The reading frame after the splice site begins with
TCT.
Chapter 30 Solutions
Biochemistry (Looseleaf)
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- Translation. Write the anti-codon sequence of the MRNA transcript. Translate the MRNA transcript into peptide sequence using both the 3 letter abbreviation and 1 letter abbreviation. ANTI-CODON 3' 5' SEQUENCE AMINO ACID N- C- SEQUENCE (3 letter terminus Abbreviation) Terminus AMINO ACID N- C- SEQUENCE (1 letter terminus Abbreviation) Terminusarrow_forwardPolymerase inhibition. Cordycepin inhibits poly(A) synthesis at low concentrations and RNA synthesis at higher concentrations. NH2 H. он Cordycepin (3'-deoxyadenosine) a. What is the basis of inhibition by cordycepin? b. Why is poly(A) synthesis more sensitive than the synthesis of other RNAS to the presence of cordycepin? c. Does cordycepin need to be modified to exert its effect?arrow_forwardRNA sequence. ate 3' and 5' ends on BOTH strands ate which strand served as the TEMPLATE strand and which ING strandarrow_forward
- tRNA enzyme. Any given aminoacyl-tRNA synthetase: a. Attaches the amino acid to the 5′-end '5end of the tRNA b. Always recognizes only one specific tRNA c. Recognizes all tRNA molecules d. Forms an ester linkage between the amino acid and the tRNAarrow_forwardBroken operators. Consider a hypothetical mutation in OR2OR 2 that blocks both A repressor and Cro binding. How would this mutation affect the likelihood of bacteriophage entering the lytic phase?arrow_forwardTrue or False. Explain. A) At no time during protein synthesis does an amino acid make direct contact with the mRNA being translated. B) Because the two strands of DNA are complementary, the mRNA of a gene can be synthesized using either strand as a template.arrow_forward
- Yes or no? No explanation. rna polymerase are recruiting to start transcription but promoters are DNA sequence. Taq polymerase is enzyme and can synthesize dna at 72 degrees. dna reads 5 to 3 and polymerase reads template 3 to 5.arrow_forwardPlssss helppppp. Describe the purpose of DNA replication. What is it and why is it important?arrow_forwardOpen reading frames... correspond to introns, which are not read by the ribosome during translation correspond to contiguous fragments of DNA sequence that do not contain a stop codon when read in a particular frame correspond to contiguous fragments of DNA sequence that do not contain a stop codon when read in any of six frames are often rich in acetylated histones which allow transcription occur when fragments of DNA sequence are highly similar between two species are recognized by ribosomes to initiate translationarrow_forward
- the correct reading frame. next thing to do is to write out the mRNA sequence using this sense strand reading frame. The last thing to do is to translate the sequence. The reading frame DNA sequence is: The mRNA sequence is: The polypeptide sequence is:arrow_forwardBe sure to answer all parts. Write a possible mRNA sequence that codes for each peptide. a. His-Cys-Tyr-Val-Ser 5¹- b. Phe-Val-Thr-Tyr-Glu 5'- 5'- c. Trp-Phe-Asn-Gln -3' U -3' с Table 26.2 The Genetic Code-Triplets in Messenger RNA First Base (5' end) -3' U UUU UUC UUA UUG CUU CUC CUA CUG AUL Phe Phe Leu Leu Leu Leu Leu Leu la C UCU UCC UCA UCG CCU CCC CCA CCG Second Base A UAU UAC UAA UAG CAU CAC CAA CAG Ser Ser Ser Ser Pro Pro Pro Pro Tyr 55 Tyr Stop Stop His His Gin Gin G UGU UGC UGA UGG CGU CGC CGA CGG Cys Cys Stop Trp Arg Arg Arg Arg Third Base (3¹ ond) DUAC DU AG с А Аarrow_forwardMultiple Matching. Fill in the blanks with the words below that apply.18. ________ site of protein synthesis19. ________ carries the codon20. ________ carries the anticodon21. ________ a process synonymous with mRNA synthesis22. ________ bacteriophages participate in this transfer23. ________ duplication of the DNA molecule24. ________ process in which transcribed DNA code is deciphered into a polypeptide25. ________ involves plasmidsreplicationtRNAconjugationribosometransductionmRNAtranscriptiontransformationtranslationnone of these PreviousNextarrow_forward
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