General Physics, 2nd Edition
2nd Edition
ISBN: 9780471522782
Author: Morton M. Sternheim
Publisher: WILEY
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Question
Chapter 31, Problem 27E
(a)
To determine
The number of times the
(b)
To determine
The number of times the radiation technologist permitted to load the source in a year.
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A Geiger counter measured the radiation in a closet and found it to be 3.6 mSv. What is this value in Sv, and is this level of radiation higher or lower than natural background radiation?
Chapter 31 Solutions
General Physics, 2nd Edition
Ch. 31 - Prob. 1RQCh. 31 - Prob. 2RQCh. 31 - Prob. 3RQCh. 31 - Prob. 4RQCh. 31 - Prob. 5RQCh. 31 - Prob. 6RQCh. 31 - Prob. 7RQCh. 31 - Prob. 8RQCh. 31 - Prob. 9RQCh. 31 - Prob. 10RQ
Ch. 31 - Prob. 1ECh. 31 - Prob. 2ECh. 31 - Prob. 3ECh. 31 - Prob. 4ECh. 31 - Prob. 5ECh. 31 - Prob. 6ECh. 31 - Prob. 7ECh. 31 - Prob. 8ECh. 31 - Prob. 9ECh. 31 - Prob. 10ECh. 31 - Prob. 11ECh. 31 - Prob. 12ECh. 31 - Prob. 13ECh. 31 - Prob. 14ECh. 31 - Prob. 15ECh. 31 - Prob. 16ECh. 31 - Prob. 17ECh. 31 - Prob. 18ECh. 31 - Prob. 19ECh. 31 - Prob. 20ECh. 31 - Prob. 21ECh. 31 - Prob. 22ECh. 31 - Prob. 23ECh. 31 - Prob. 24ECh. 31 - Prob. 25ECh. 31 - Prob. 26ECh. 31 - Prob. 27ECh. 31 - Prob. 28ECh. 31 - Prob. 29ECh. 31 - Prob. 30ECh. 31 - Prob. 31ECh. 31 - Prob. 32ECh. 31 - Prob. 33ECh. 31 - Prob. 34ECh. 31 - Prob. 35ECh. 31 - Prob. 36ECh. 31 - Prob. 37ECh. 31 - Prob. 38ECh. 31 - Prob. 39ECh. 31 - Prob. 40ECh. 31 - Prob. 41ECh. 31 - Prob. 42ECh. 31 - Prob. 43ECh. 31 - Prob. 44ECh. 31 - Prob. 45ECh. 31 - Prob. 46ECh. 31 - Prob. 47ECh. 31 - Prob. 48ECh. 31 - Prob. 49ECh. 31 - Prob. 50ECh. 31 - Prob. 51ECh. 31 - Prob. 52ECh. 31 - Prob. 53ECh. 31 - Prob. 54ECh. 31 - Prob. 55ECh. 31 - Prob. 57E
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- Find the radiation dose in Gy for: (a) A 10-mSv fluoroscopic X-ray series, (b) 50 mSv of skin exposure by an a emitter, (c) 160 mSv of and rays from the 40K in your body.arrow_forwardCalculate the dose in Sv to the chest at a patient given an xray under the following conditions. The xray beam intensity is 1.50 W/m2, the area of the chest exposed is 0.0750 m2 35.0% of the xrays are absorbed in 20.0 kg of tissue, and the exposure time is 0.250 s.arrow_forwardData from the appendices and the periodic table may be needed for these problems. Show that the activity of the 14C in 1.00 g of 12C found in living tissue is 0.250 Bq.arrow_forward
- A beam of 168MeV nitrogen nuclei is used for cancer therapy. If this beam is directed onto a 0.200kg tumor and gives it a 2.00Sv dose, how many nitrogen nuclei were stopped? (Use an RBE of 20 for heavy ions.)arrow_forwardData from the appendices and the periodic table may be needed for these problems. (a) Calculate the activity R in curies at 1.00 g of 226Ra. (b) Discuss why your answer is not exactly 1.00 Ci, given that the curie was originally supposed to be exactly the activity of a gram of radium.arrow_forwardHow many Gy of exposure is needed to give a cancerous tumor a dose of 40 Sv if it is exposed to acfivity?arrow_forward
- What is the dose in mSv for: (a) a 0.1-Gy X-ray? (b) 2.5 mGy of neutron exposure to the eye? (c) 1.5m Gy of a exposure?arrow_forwardFind the radiation dose in Gy for: (a) A 10mSv fluoroscopic xray series. (b) 50 mSv of skin exposure by an emitter. (c) 160 mSv of and rays from the 40K in your body.arrow_forwardIf everyone in Australia received an extra 0.05 mSv per year of radiation, what would be the increase in the number of cancer deaths per year? (Assume that time had elapsed for the effects to become apparent.) Assume that there are 200104 deaths per Sv of radiation per year. What percent at the actual number of cancer deaths recorded is this?arrow_forward
- Data from the appendices and the periodic table may be needed for these problems. A 60Co source is labeled 4.00 mCi, but its present activity is found to be 1.85107Bq. (a) What is the present activity in mCi? (b) How long ago did it actually have a 4.00—mCi activity?arrow_forwardSuppose one load irradiation plant uses a 137Cs source while another uses an equal activity of 60Co. Assuming equal fractions of the (rays from the sources are absorbed, why is more time needed to get the same dose using me 137Cs source?arrow_forward(a) Calculate the energy released in the neutroninduced fission (similar to the spontaneous fission in Example 32.3) n+238U96Sr+140Xe+3n, given m(96Sr)=95.921750u and m(140Xe)=139.92164. (b) This result is about 6 MeV greater than the result for spontaneous fission. Why? (c) Con?rm that the total number at nucleons and total charge are conserved in this reaction.arrow_forward
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