   Chapter 31, Problem 47PE

Chapter
Section
Textbook Problem

Data from the appendices and the periodic table may be needed for these problems.Show that the activity of the 14C in 1.00 g of 12C found in living tissue is 0.250 Bq.

To determine

To show:

That the activity of 14C in 1g of 12C in living tissue is 0.250Bq .

Explanation

Introduction:

The number of radioactive nuclei in a sample decreases with time.

Activity of a radioactive nuclei in a given sample shows the rate of decay.

To find the activity we need to find number of carbon-14 nuclei in 1kg sample of 12C.

N12c=6.023×1023mol-112.0gmol-1×1000g=5.02×1025

As, the abundance of 14C in 1kg sample of 12C is 1.3×1012 . Therefore,

N14c=1.3×1012×5.02×1025=6.52×1013

The half-life of 14C is 5730y.

Activity of 14C in 1kg sample of 12C is,

R=0

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

The BMI standard is an excellent tool for evaluating obesity in athletes and the elderly. T F

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

How do eating disorders affect health?

Understanding Nutrition (MindTap Course List)

What causes an aging giant star to produce a planetary nebula?

Horizons: Exploring the Universe (MindTap Course List) 