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College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000

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BuyFindarrow_forward

College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000
Textbook Problem

Data from the appendices and the periodic table may be needed for these problems.

Show that the activity of the 14C in 1.00 g of 12C found in living tissue is 0.250 Bq.

To determine

To show:

That the activity of 14C in 1g of 12C in living tissue is 0.250Bq .

Explanation

Introduction:

The number of radioactive nuclei in a sample decreases with time.

Activity of a radioactive nuclei in a given sample shows the rate of decay.

To find the activity we need to find number of carbon-14 nuclei in 1kg sample of 12C.

  N12c=6.023×1023mol-112.0gmol-1×1000g=5.02×1025

As, the abundance of 14C in 1kg sample of 12C is 1.3×1012 . Therefore,

  N14c=1.3×1012×5.02×1025=6.52×1013

The half-life of 14C is 5730y.

Activity of 14C in 1kg sample of 12C is,

  R=0

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