Chapter 3.4, Problem 16PPS

To determine

To write in slope intercept form for the line that having slope $12$ and y-intercept is .Then graph the line.

Answer to Problem 16PPS

Line

  $y=12x+\frac{4}{5}$

Graph

Explanation of Solution

Given information:

The line having slope and y-intercept

  $m:12$

  $b:\frac{4}{5}$

Formula used:

Slope intercept form

  $y=mx+b$

Calculation:

The line having slope and y-intercept

  $m:12$

  $b:\frac{4}{5}$

The general slope intercept form is given as

  $y=mx+b$

Where

  $m$ is slope

  $b$ is y-intercept

Then

  $b:\frac{4}{5}$

Substitute value of slope and y-intercept in general slope intercept form

  $y=12x+\frac{4}{5}$

Substituting $x=0$

Then

  $y=\frac{4}{5}$

Substituting $y=0$

Then

  $0=12x+\frac{4}{5}$

On solving

  $12x=-\frac{4}{5}$

On solving

  $3x=-\frac{1}{5}$

On solving

  $x=-\frac{1}{15}$

Table

Then graph