Concept explainers
a.
To determine which species experienced a greater rate of change in population.
a.
Answer to Problem 45PPS
The population of Michigan Bald is increasing with greater rate.
Explanation of Solution
Given information :
Let us take two points on the graph (1992, 440) and (2006, 9464)
Slope of the line containing these two points shall represent the rate of change.
We know that the slope of a line is given by the formula,
Now rate of change of Michigan Bald population is,
Similarly Let us take two points on the graph (1992, 50) and (2006, 361)
Rate of change of Wolf populations is,
Now comparing both we can conclude that the population of Michigan Bald is increasing with greater rate.
b.
To plot the graph of both populations.
b.
Explanation of Solution
Given information :
The attendance in 2001 was 450,746
The attendance in 2005 was 457,373
Red line is for Michigan Bald.
Blue line is for Gray Wolf
c.
To determine population in 2012.
c.
Answer to Problem 45PPS
The population of Michigan Bald will be around 1189 in 2012.
The population of Gray Wolf will be around 494 in 2012.
Explanation of Solution
Given information :
The attendance in 2001 was 450,746
The attendance in 2005 was 457,373
Let us take two points on the graph (1992, 440) and (2012, x )
Hence the population in 2012 of Michigan Bald is,
Hence the population of Michigan Bald will be around 1189 in 2012.
Similarly for Gray Wolf,
Take two points on the graph (1992, 50) and (2012, x )
Now the population in 2012 is,
Hence the population of Gray Wolf will be around 494 in 2012.
Chapter 3 Solutions
Geometry, Student Edition
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