Chapter 3.4, Problem 17PPS

To determine

To write in slope intercept form for the line that having slope $-\frac{3}{4}$ and containing .Then graph the line.

Answer to Problem 17PPS

Line

  $y=-\frac{3}{4}x+4$

Graph

Explanation of Solution

Given information:

The line having slope and point

  $m:-\frac{3}{4}$

  $(0,4)$

Formula used:

Point-slope form

  $y-y_1=m(x-x_1\text{) }$

Calculation:

The line having slope and point

  $m=-\frac{3}{4}$

  $(0,4)$

Here

  $x_1=0$

  $y_1=4$

Substitute value of slope and point in the point-slope form

  $y-4=-\frac{3}{4}(x-0\text{) }$

On solving

  $y-4=-\frac{3}{4}x$

Add 4 both sides

  $y-4+4=-\frac{3}{4}x+4$

On solving

  $y=-\frac{3}{4}x+4$

Substituting $x=0$

Then

  $y=4$

Substituting $y=0$

Then

  $\text{0}=-\frac{3}{4}x+4$

On solving

  $\frac{3}{4}x=4$

On solving

  $x=\frac{16}{3}$

Table

Then graph