Chapter 3.4, Problem 2CYP

To determine

To write in point-slope form for the line that having the given slope that contains the given point point.Then graph.

  $m:4$

  $(-3,-6)$

Answer to Problem 2CYP

Point-slope form

  $y+6=\text{4}(x+3)$

Graph

Explanation of Solution

Given information:

The line having slope and point

  $m:4$

  $(-3,-6)$

Formula used:

Point-slope form

  $y-y_1=m(x-x_1)$

Calculation:

The line having slope and point

  $m:4$

  $(-3,-6)$

Here

  $x_1=-3$

  $y_1=-6$

The general point-slope form is given as

  $y-y_1=m(x-x_1)$

Where

  $m$ is slope

Substitute value of slope and point in general point-slope form

  $y-(-6)=\text{4}(x-(-3))$

On solving

  $y+6=\text{4}(x+3)$

On solving

  $y+6=\text{4}x+12$

On solving

  $y=\text{4}x+6$

Substituting $x=0$

Then

  $y=6$

Substituting $y=0$

Then

  $\text{0}=\text{4}x+6$

On solving

  $x=-\frac{3}{2}$

Table

Then graph