Coherent light rays of wavelength λ strike a pair of slits separated by distance d at an angle θ 1 with respect to the normal to the plane containing the slits as shown in Figure P36.9. The rays leaving the slits make an angle θ 2 with respect to the normal, and an interference maximum is formed by those rays on a screen that is a great distance from the slits. Show that the angle θ 2 is given by θ 2 = sin − 1 ( sin θ 1 − m λ d ) where m is an integer. Figure P36.9
Coherent light rays of wavelength λ strike a pair of slits separated by distance d at an angle θ 1 with respect to the normal to the plane containing the slits as shown in Figure P36.9. The rays leaving the slits make an angle θ 2 with respect to the normal, and an interference maximum is formed by those rays on a screen that is a great distance from the slits. Show that the angle θ 2 is given by θ 2 = sin − 1 ( sin θ 1 − m λ d ) where m is an integer. Figure P36.9
Solution Summary: The formula to calculate the path difference between upper and lower slits is delta =AB-DC.
Coherent light rays of wavelength λ strike a pair of slits separated by distance d at an angle θ1 with respect to the normal to the plane containing the slits as shown in Figure P36.9. The rays leaving the slits make an angle θ2 with respect to the normal, and an interference maximum is formed by those rays on a screen that is a great distance from the slits. Show that the angle θ2 is given by
In a two-slit experiment, the slit separation is 3.00*10-5 m. The interference pattern is recorded on a flat screen-like detector that is 2.00 m away from the slits. If the seventh bright fringe on the detector is 10.0 cm away from the central fringe, what is the wavelength of the light passing through the slits?
A) 100 nm
B) 204 nm
C) 214 nm
D) 224 nm
E) 234 nm
A double-slit experiment has a slit separation distance of 0.08 mm. If the bright interference fringes are to be spaced 5 mm apart on the screen when the slits are illuminated with a laser of wavelength 633 nm, what should be the distance to the screen from the slits?
a) 0.42 m
b) 0.63 m
c) 0.77 m
d) 0.81 m
e) 0.92 m
In a Young’s double-slit experiment, light of wavelength 500 nm illuminates two slits that are separated by 1 mm. What is the separation distance between the central maximum (m = 0) and the 3rd order maximum (m = 3) on a screen 5.0 m from the slits?
A. 0.10 cm.
B. 0.25 cm.
C. 0.50 cm.
D. 0.75 cm.
E 1.0 cm.
Chapter 37 Solutions
Physics for Scientists and Engineers, Technology Update (No access codes included)
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