Stats: Modeling the World Nasta Edition Grades 9-12
Stats: Modeling the World Nasta Edition Grades 9-12
3rd Edition
ISBN: 9780131359581
Author: David E. Bock, Paul F. Velleman, Richard D. De Veaux
Publisher: PEARSON
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Chapter 4, Problem 11E

(a)

To determine

To Explain: the mean and median to be larger expected.

(a)

Expert Solution
Check Mark

Explanation of Solution

Given:

  Stats: Modeling the World Nasta Edition Grades 9-12, Chapter 4, Problem 11E , additional homework tip  1

When the distribution is positively or right skewed the relation between mean, median and mode is

Mean > Median > Mode

For the negatively or left skewed the relation should be

Mean < Median < Mode

By seeing the distribution, it is shows that the distribution is right skewed because the large tail looks on the right side of the distribution. So for the positively skewed distribution or right side skewed distribution, mean is greater than median. Hence the histogram would expect the mean to be larger.

(b)

To determine

To Explain: the few sentences describing this distribution.

(b)

Expert Solution
Check Mark

Explanation of Solution

Given:

  Stats: Modeling the World Nasta Edition Grades 9-12, Chapter 4, Problem 11E , additional homework tip  2

By seeing the histogram, there are two peaks in the histogram one is at 1 and another is at 8 days. So the distribution is bimodal and skewed to right. On the basis of the height of the bars in the histogram, most of the patient stays in between 1 and 15 and there are some extreme values above 25 days.

(c)

To determine

To Explain: the summary statistics would choose to summarize the centre and spread in these data.

(c)

Expert Solution
Check Mark

Explanation of Solution

Given:

  Stats: Modeling the World Nasta Edition Grades 9-12, Chapter 4, Problem 11E , additional homework tip  3

By seeing the distribution, the data is skewed. Mean and Inter quartile range would be selected to summarize the centre and spread for this data.

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