Organic Chemistry
Organic Chemistry
4th Edition
ISBN: 9780077479824
Author: SMITH, Janice Gorzynski/
Publisher: McGraw-Hill College
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Chapter 4, Problem 4.60P
Interpretation Introduction

(a)

Interpretation: The chair forms of galactose are to be drawn. The more stable conformation of galactose is to be labeled.

Concept introduction: Carbohydrates are naturally occurring compounds. Carbohydrates are polyhydroxy aldehydes and ketones. Galactose is a aldohexose as it contains six carbon atoms as well as an aldehyde functional group. The molecular formula of galactose is C6H12O6.

The stereocenters are carbon atoms on which the interchanging of two atoms or groups results in the formation of new stereoisomers.

Interpretation Introduction

(b)

Interpretation: Among galactose and glucose, the sugar that is more stable is to be identified. The explanation corresponding to the correct choice is to be stated.

Concept introduction: Carbohydrates are naturally occurring compounds. Carbohydrates are polyhydroxy aldehydes and ketones. Galactose is a aldohexose as it contains six carbon atoms as well as an aldehyde functional group. The molecular formula of galactose is C6H12O6.

The stereocenters are carbon atoms on which the interchanging of two atoms or groups results in the formation of new stereoisomers.

Interpretation Introduction

(c)

Interpretation: The constitutional isomer of galactose is to be drawn.

Concept introduction: Carbohydrates are naturally occurring compounds. Carbohydrates are polyhydroxy aldehydes and ketones. Galactose is a aldohexose as it contains six carbon atoms as well as an aldehyde functional group. The molecular formula of galactose is C6H12O6.

The stereocenters are carbon atoms on which the interchanging of two atoms or groups results in the formation of new stereoisomers.

Constitutional isomers have the same molecular formula but they differ in the pattern in which atoms are connected. They contain different functional groups and/or bonding patterns.

Interpretation Introduction

(d)

Interpretation: A stereoisomer of galactose that is different from glucose is to be drawn.

Concept introduction: Carbohydrates are naturally occurring compounds. Carbohydrates are polyhydroxy aldehydes and ketones. Galactose is a aldohexose as it contains six carbon atoms as well as an aldehyde functional group. The molecular formula of galactose is C6H12O6.

The stereocenters are carbon atoms on which the interchanging of two atoms or groups results in the formation of new stereoisomers.

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Chapter 4 Solutions

Organic Chemistry

Ch. 4 - Problem 4.9 Give the structure corresponding to...Ch. 4 - Prob. 4.12PCh. 4 - Give the IUPAC name for each compound.Ch. 4 - Give the structure corresponding to each IUPAC...Ch. 4 - Arrange the following compounds in order of...Ch. 4 - Problem 4.14 Draw the staggered and eclipsed...Ch. 4 - Prob. 4.17PCh. 4 - a.Draw the three staggered and three eclipsed...Ch. 4 - Problem 4.19 Consider rotation around the...Ch. 4 - Calculate the destabilization present in each...Ch. 4 - Problem 4.21 Classify the ring carbons as up or...Ch. 4 - Draw a second chair conformation for each...Ch. 4 - Prob. 4.23PCh. 4 - Problem 4.25 Draw the structure for each compound...Ch. 4 - For cis-1, 3-diethylcyclobutane, draw a a...Ch. 4 - Prob. 4.26PCh. 4 - Problem 4.28 Consider . Draw structures f or the...Ch. 4 - Problem 4.29 Draw a chair conformation of...Ch. 4 - Prob. 4.29PCh. 4 - Draw the products of each combustion reaction.Ch. 4 - Explain why beeswax is insoluble in H2O, slightly...Ch. 4 - Prob. 4.32PCh. 4 - Name each alkane using the ball-and-stick model,...Ch. 4 - Consider the substituted cyclohexane shown in the...Ch. 4 - Prob. 4.35PCh. 4 - 3.31 For each alkane: (a) classify each carbon...Ch. 4 - Prob. 4.37PCh. 4 - Prob. 4.38PCh. 4 - Give the IUPAC name for each compound. a. h.k....Ch. 4 - 4.39 Give the structure and IUPAC name for each of...Ch. 4 - 4.40 Draw the structure corresponding to each...Ch. 4 - Prob. 4.42PCh. 4 - Prob. 4.43PCh. 4 - 4.42 Give the IUPAC name for each compound. a....Ch. 4 - Prob. 4.45PCh. 4 - Prob. 4.46PCh. 4 - 4.45 Which conformation in each pair is higher in...Ch. 4 - Considering rotation around the bond highlighted...Ch. 4 - Prob. 4.49PCh. 4 - Prob. 4.50PCh. 4 - 4.49 Label the sites of torsional and steric...Ch. 4 - Prob. 4.52PCh. 4 - 4.51 The eclipsed conformation of is less...Ch. 4 - (a) Draw the anti and gauche conformations for...Ch. 4 - For each compound drawn below: a.Label each OH,Br...Ch. 4 - Draw the two possible chair conformations for...Ch. 4 - For each compound drawn below: a. Draw...Ch. 4 - 4.56 Convert each of the following structures into...Ch. 4 - Prob. 4.59PCh. 4 - Prob. 4.60PCh. 4 - Classify each pair of compounds as constitutional...Ch. 4 - Prob. 4.62PCh. 4 - Prob. 4.63PCh. 4 - 4.62 Draw the three constitutional isomers having...Ch. 4 - Prob. 4.65PCh. 4 - Prob. 4.66PCh. 4 - 4.65 Hydrocarbons like benzene are metabolized in...Ch. 4 - Which of the following compounds are lipids?Ch. 4 - Prob. 4.69PCh. 4 - Prob. 4.70PCh. 4 - Cyclopropane and cyclobutane have similar strain...Ch. 4 - Prob. 4.72PCh. 4 - Haloethanes (CH3CH2X,X=Cl,Br,I) have similar...Ch. 4 - Prob. 4.74PCh. 4 - Prob. 4.75PCh. 4 - Consider the tricyclic structure B (a) Label each...Ch. 4 - Read Appendix B on naming branched alkyl...Ch. 4 - Read Appendix B on naming bicyclic compounds. Then...
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