Concept explainers
Interpretation: The most acidic
Concept introduction: Electronegative elements have tendency to attract electrons towards it. Since electrons are shared more towards electronegative element, it acquires partial negative charge on it. As a result, other bonded atom develops partial positive charge. Polarization in any molecule arises due to electronegativity difference between bonded atoms. Polarization that is caused by electronegative atom can induce polarization in neighboring bonds to very small extent. This effect is known as inductive effect. Due to this effect, hydrogen attached to positive atom becomes more acidic than that on neutral atom. This also explains more acidic nature of hydrogens attached to electronegative atoms as compared to other atoms.
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Chapter 4 Solutions
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- Construct an explanation for why sulfuric acid is such a strong acid. (Note that sulfur is in thethird row of the periodic table and can have more than eight electrons.)arrow_forwardDraw the structure of the conjugate base of water. (Note that it does not appear in Figure 4.11).arrow_forwardFor each structure you drew in the answer to the previous question, classify it as a strong acid,strong base, weak acid, or weak base.arrow_forward
- Also can you provide an explanation along with the drawing as to how you come up with the answer please.arrow_forwardCan you please answer this and if possible can you show me a explanation?arrow_forwardWhy couldn't it be the H on the other side? Is it specific that only that one H can be the most acidic? Or does it not really matter because orienting the whole molecule such that we are looking at the opposite side of it, it is the same?arrow_forward
- Below is the structure of chloroquine. Circle the basic sites on the molecule.arrow_forwardAnswer letter b. Letter A is just a guide question ( no answer needed basically)arrow_forwardUse curved arrows to show the most likely acid-base reaction between phenol and NaOH. a. Use pKa data to mark each curved arrow with a positive or negative energy change in pKa ,units. b. Calculate H for this reaction, and sketch an energy diagram showing H as an arrow onyour diagram.arrow_forward
- Consider the following bases: a. For each base above, circle the atom/atoms with the highest PE (will release the most P.E.when a lone pair on this atom combines with an H+ ) b. Rank the bases 1 (highest P.E./strongest base) to 7 (lowest PE/weakest base), and explainyour reasoning.arrow_forwardFor each molecule below, draw the conjugate acid or conjugate base or both if the molecule hasboth a conjugate acid and a conjugate base (e.g., water).arrow_forwardBe sure to answer all parts. The pk of three different C-H bonds is given below. For each compound, draw the conjugate base, including all possible resonance structures for compound C. Use skeletal structures when drawing all conjugate bases. compound A H H H pK₂ = 50 Conjugate base of compound A: Conjugate base of compound B: Conjugate base of compound C: edit structure ... compound B resonance structure (negative charge on C) H H edit structure ... (one Lewis structure) edit structure ... (one resonance structure) X H pka = 43 compound C edit structure ... H H pK₂ = 19.2 resonance structure (negative charge on O) Harrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
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