a.
Diver velocity at the instant of hiting the water.
a.
Answer to Problem 54A
When diver hits the water his velocity will be 14 m/sec.
Explanation of Solution
Given :
Mass of diver
Height of tower
Formula used :
According to third equation of motion,
Where,
u is initial velocity
v is final velocity
g is acceleration due to gravity
h is height.
Calculation:
When the diver jumps off his initial velocity is
Acceleration due to gravity is
Now, substitute the value of u, g and hin equation of motion.
Conclusion:
Therefore, when diver hits the water his velocity will be 14 m/sec.
b.
Net force exerted by the water.
b.
Answer to Problem 54A
Net force exerted by water is 3185 N.
Explanation of Solution
Given :
Mass of diver
Distance travelled
Formula used :
According to third equation of motion,
Where,
u is initial velocity
v is final velocity
g is acceleration due to gravity
h is height.
Also, the force is
Where,
m is mass
a is acceleration
Calculation:
When the diver jumps off his initial velocity
After travelling a distance of 2 m diver finally stops
Therefore, final velocity of diver is
Substitute the value of u, v and s.
Now, substitute the value of m and ain the equation of force.
Here, negative sign indicates that direction of force is in opposite direction of motion.
Conclusion:
Therefore, the force exerted by water in opposite direction with a magnitude of 3185 N.
Chapter 4 Solutions
Glencoe Physics: Principles and Problems, Student Edition
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