Chapter 4, Problem 96A

To determine

The time at which the skier passes the house of $\text{B}$ .

Answer to Problem 96A

The skier passes the house of $\text{B}$ at $9:04\text{AM}$ .

Explanation of Solution

Given:

The distance between the house of two persons T and $\text{B}$ is $d=5.2\text{km}$ .

Consider the skier passes the house of T at $8:25\text{AM}$ .

The average speed of the skier is $\overline{v}=8.0\text{km/h}$ .

Formula used:

Consider an object covers a distance $d$ in time $t$ . Then, the average velocity $\left(\overline{v}\right)$ of the object is as follows:

  $\overline{v}=\frac{d}{t}$

Calculation:

Find the time taken for the skier for the travel between T and person B’s house as follows:

  $\begin{array}{c}t=\frac{d}{\overline{v}}\\ =\frac{5.2\text{km}}{8\text{km/h}}\\ =0.65\text{h}\times \left(\frac{60\text{min}}{1\text{h}}\right)\\ =39\text{min}\end{array}$

The skier takes $39\text{min}$ to travel from T’s house to B’s house.

The skier passes the house of T at $8:25\text{AM}$ .

Then the skier will take $\left(8:25+0:39\right)=9:04\text{AM}$ to pass the house of $\text{B}$ .

Hence, the skier passes the house of $\text{B}$ at $9:04\text{AM}$ .

Conclusion:

Thus, the skier passes the house of $\text{B}$ at $9:04\text{AM}$ .