Chapter 4, Problem 76A

To determine

The magnitude of the acceleration of the toward the girl.

Answer to Problem 76A

The magnitude of the acceleration of the toward the girl is $2.08\text{m}/{\text{s}}^2$ .

Explanation of Solution

Given Info:

The mass of the boy is, $m_b=65\text{kg}$ .

The mass of the girl is, $m_g=45\text{kg}$ .

The acceleration of the girl toward the boy is, $a_g=3\text{m}/{\text{s}}^2$ .

Formula Used:

The expression to calculate the magnitude of the acceleration of the toward the girl is,

  $a_b=\frac{m_g{a}_g}{m_b}$

Calculation:

Substitute all the values in the above expression.

  $\begin{array}{c}{a}_b=\frac{\left(45\text{kg}\right)\left(3\text{m}/{\text{s}}^2\right)}{65\text{kg}}\\ =2.08\text{m}/{\text{s}}^2\end{array}$

Thus, the magnitude of the acceleration of the toward the girl is $2.08\text{m}/{\text{s}}^2$ .