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ChemistryPrinciples of Instrumental AnalysisRoot-mean-square thermal noise associated with a resister should be calculated. The fate of the thermal noise when the bandwidth is reduced to 100 Hz should be predicted. Concept introduction: Data given: Temperature (T) = Room temperature = 298 K Bandwidth ( Δ f ) = 1 MHz Resistance of the resistor (R) = 1.0 M Ω Thermal noise for a resistive circuit element can be given as υ ¯ r m s = 4 k T R Δ f Where, k = Boltzmann's constant = 1 .38 × 10 − 23 J/K T = Temperature in K R = Resistance in Ω Δ f = BandwidthStart your trial now! First week only $4.99!*arrow_forward*

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7th Edition

Douglas A. Skoog + 2 others

Publisher: Cengage Learning

ISBN: 9781305577213

Chapter 5, Problem 5.9QAP

Interpretation Introduction

**Interpretation:**

Root-mean-square thermal noise associated with a resister should be calculated. The fate of the thermal noise when the bandwidth is reduced to

**Concept introduction:**

Data given:

Temperature (T) = Room temperature =

Bandwidth (

Resistance of the resistor (R) =

Thermal noise for a resistive circuit element can be given as