An incompressible fluid of density and viscosity
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FLUID MECHANICS FUNDAMENTALS+APPS
- Two infinite plates a distance h apart are parallel to the xzplane with the upper plate moving at speed V, as inFig. There is a fluid of viscosity μ and constant pressurebetween the plates. Neglecting gravity and assumingincompressible turbulent flow u(y) between the plates, usethe logarithmic law and appropriate boundary conditions toderive a formula for dimensionless wall shear stress versusdimensionless plate velocity. Sketch a typical shape of theprofile u(y).arrow_forward338 B/s O 1: 56% E 3:01 Question: Gasoline is flowing through this 180° pipe bend. The pipe cross-sectional area is 18 in?. Take the pipe weight as 5 Kg. Flow rate is 0.5 liters/s. Pressure at section-1 6 psia, pressure at section-2 is 4 psia. Calculate the anchoring force required to hold this pipe and also show its direction, referenced to proper 2-dimensional a cartesian coordinate system. (2 1arrow_forwardAn incompressible fluid (kinematic viscosity, 7.4 x10-7 m²/s, specific gravity, 0.88) is held between two parallel plates. If the top plate is moved with a velocity of 0.5 m/s while the bottom one is held stationary, the fluid attains a linear velocity profile in the gap of 0.5 mm between these plates; the shear stress in Pascals on the surface of top plate is (a) 0.651 x 10-3 (c) 6.51 (b) 0.651 (d) 0.651 x 103arrow_forward
- Laminar Flow in a Vertical Cylindrical Annulus Derive the equation for steady-state laminar flow inside the annulus between two concentric vertical pipes. This type of flow occurs often in concentric pipe heat exchangers. max velocity profilearrow_forwardTake the full-blown Couette flow as shown in the figure. While the upper plate is moving and the Lower Plate is constant, flow occurs between two infinitely parallel plates separated by the H distance. The flow is constant, uncompressed, and two-dimensional in the X-Y plane. In fluid viscosity µ, top plate velocity V, distance h, fluid density ρ, and distance y, create a dimensionless relationship for component X of fluid velocity using the method of repeating variables. Show all steps in order.arrow_forwardTake the densilty and pressure values at 7km, and then apply Bernoulli equation. I think this is the method to solve the problem,If there any you can proceed with that. Please do it fast ,Very urgent. Question 1: . Consider an airplane flying at a standard altitude of 7 km with a velocity of 300 m/s. At a point on the wing of the airplane, the velocity is 400 m/s. Calculate the pressure at this point.arrow_forward
- At a point in a pipe that lay flat ノ water in the pipe flows at a speed of 9.0 mls and has 6-40x 104 Pa a gaoge pressure is Find the gauge pressure at point 2 of pipe that lower than the first point 8.0 m and the cvoss - se ctional| area of the pipe is double of first point . Answer [1.52x105 Pa]arrow_forwardWhen a person ice skates, the surface of the ice actuallymelts beneath the blades, so that he or she skates on a thinsheet of water between the blade and the ice.( a ) Find an expression for total friction force on the bottomof the blade as a function of skater velocity V , bladelength L , water thickness (between the blade and theice) h , water viscosity μ , and blade width W .( b ) Suppose an ice skater of total mass m is skatingalong at a constant speed of V 0 when she suddenlystands stiff with her skates pointed directly forward,allowing herself to coast to a stop. Neglecting frictiondue to air resistance, how far will she travelbefore she comes to a stop? (Remember, she iscoasting on two skate blades.) Give your answer forthe total distance traveled, x , as a function of V 0 , m ,L , h , μ , and W .( c ) Find x for the case where V 0 = 4.0 m/s, m = 100 kg,L = 30 cm, W = 5.0 mm, and h = 0.10 mm. Do youthink our assumption of negligible air resistance is agood one?arrow_forwardAs can often be seen in a kitchen sink when the faucet isrunning, a high-speed channel fl ow ( V 1 , h 1 ) may “jump” toa low-speed, low-energy condition ( V 2 , h 2 ) as in Fig. . The pressure at sections 1 and 2 is approximately hydrostatic,and wall friction is negligible. Use the continuity andmomentum relations to fi nd h 2 and V 2 in terms of ( h 1 , V 1 ).arrow_forward
- Find the velocity in the center, and velocity profile for giving system : p = 1000| kg/m' , µ= 0.03 *10* pa. , ū = 0.92 m/s , d= 0.28 m ? (Hi expertises this question is from Mechanical fluid.) I need answer quickly.arrow_forwardQ3/The open tank in the figure contains water at 20°C and is being filled through section 1. Assume incompressible flow. First derive an analytic expression for the water-level change dh/dt in terms of arbitrary volume flows (Q1, Q2, Q3) and tank diameter d. Then, if the water level h is constant, determine the exit velocity V2 for the given data Vi is 3 m/s and Q3 is 0.01 m³/s. I =0.01 m/s 2. D, = 5 cm D=7 cm Waterarrow_forwardHello sir Muttalibi is a step solution in detailing mathematics the same as an existing step solution EXAMPLE 6-1 Momentum-Flux Correction Factor for Laminar Pipe Flow CV Vavg Consider laminar flow through a very long straight section of round pipe. It is shown in Chap. 8 that the velocity profile through a cross-sectional area of the pipe is parabolic (Fig. 6-15), with the axial velocity component given by r4 V R V = 2V 1 avg R2 (1) where R is the radius of the inner wall of the pipe and Vavg is the average velocity. Calculate the momentum-flux correction factor through a cross sec- tion of the pipe for the case in which the pipe flow represents an outlet of the control volume, as sketched in Fig. 6-15. Assumptions 1 The flow is incompressible and steady. 2 The control volume slices through the pipe normal to the pipe axis, as sketched in Fig. 6-15. Analysis We substitute the given velocity profile for V in Eq. 6-24 and inte- grate, noting that dA, = 2ar dr, FIGURE 6–15 %3D Velocity…arrow_forward
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