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(a) The transistor parameters are
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Microelectronics: Circuit Analysis and Design
- Since Vcc = 25 V, Vi = 36 mV, RB = 470 kΩ, RC = 3.1 kΩ, RE1 = 470 Ω, RE2 = 1.2 kΩ, RL = 56.2 kΩ and β = 110 in the circuit in the figure, find the value of the output voltage (Vo). NOTE-1: Capacitors are negligible at mid-band frequency. NOTE-2: The output impedance (r0) of the transistor will be neglected.arrow_forwardA bipolar transistor is operating with vBE =+0.7 V and vBC = +0.3 V. By the strict definitionsgiven in the chapter on bipolar transistors, this transistoris operating in the saturation region. Use thetransport equations to demonstrate that it actuallybehaves as if it is still in the forward-active region.Discuss this result. (You may use IS = 10−15 A,αF = 0.98, and αR = 0.2.)arrow_forwardAn npn transistor with IS = 1 × 10−16 μA, αF =0.975, and αR = 0.5 is operating with VB E = 0.70 Vand VBC = 0.50 V. By definition, this transistor isoperating in the saturation region. However, in thediscussion it was noted that this transistor actually behaves as if it is still in the forwardactive region even though VBC > 0. Why? Use thetransport model equations to justify your answerarrow_forward
- The transistor is specified to have Bf in the range of 7 to 35. The load resistance is Rc = 9 ohms. The dc supply voltage is Vcc = 180V and the input voltage to the base circuit is VB = 8V. If VCE (Sat) = 1,1 V and VBE (sat) = 1,6, determine: The value of RB that results in an ODF of 4 A. 0,7514 ohm B 0,5634 ohm C. 0,5081ohm D. 1 ohm The Power loss in the Transistor A. 35,07 W B. 44,30 W c. 40,04 W D. 23,65 Warrow_forwardSince Vcc = 12 V, Vin = 690 mV, RB = 780 kΩ, RC1 = 27.9 Ω, RC2 = 25.4 Ω, RE = 470 Ω, RL = 47 Ω and β1 = β2 = 100 in the circuit in the figure Find the current (IL) flowing through RL? NOTE-1: VBE1 = VBE2 = 0.7 V will be taken. NOTE-2: Output impedances of transistors (r0) will be neglected. a. 16,56 mA b. 23,46 mA c. 8,28 mA d. 17,94 mA e. 20,70 mA f. 13,80 mA g. 26,22 mA h. 11,04 mAarrow_forwardthe emitter-biased small signal amplifier circuit seen.VCC= +20V, RB= 430kΩ, RC= 2kΩ, RE= 1kΩ, RL= 2.2kΩ, C1=C2= 10μF and β= 50.a. Draw the ac equivalent network circuit with re model.b. Find re using Kirchhoff’s current and voltage laws.c. Assume ro=∞ Ω and find Zi, Zo and Av.Assume that a voltage source Vs with an internal resistance Rs of 1kΩ is connected to Vi. Regarding to low frequency response,d. Find the cut-off frequency f1 due to the capacitor C1.e. Find the cut-off frequency f2 due to the capacitor C2 (assume ro=∞ Ω)arrow_forward
- In the circuit given in the figure, what is the voltage gain (Av) of the circuit when = 100, r0 = 40 kΩ, RB = 360 kΩ, RC = 3.3 kΩ, RE = 220 Ω, Rs = 15 kΩ and RL = 166 kΩ?NOTE-1: The output impedance r0 of the transistor will be taken into the calculations.NOTE-2: Capacitors are negligible at mid-band frequency.arrow_forwardPlease analyze the circuit and determine the voltage gain of both (Av,dc = Vc/Vb for DC analysis) and (Av,ac = Vo/Vs for AC analysis) where RB = 450K, Rs = 80, Ci = 47 uF, RC = 3.3K, Co = 4.7 uF, RL = 100K. In addition, find the output equivalent resistance from the Vo terminal (in AC) and the input equivalent resistance from the Vs terminal (in AC). Hint: the transistor is a Si-based one. You have to write all the calculation details and verbal explanations. You can calculate hie = beta * 26mV / Ie (mA, dc) and use the hoe as an open circuit.arrow_forwardThe ac equivalent circuit for an amplifier is shown . Assume the capacitors have infinite value, RI = 10 kΩ, RG = 1 MΩ, RD = 3.9 kΩ, and R3 = 33 kΩ. Calculate the voltage gain for the amplifier if the MOSFET Q-pointis (2 mA, 7.5 V). Assume Kn = 1 mA/V2 and λ = 0.015 V−1.arrow_forward
- ı just need the fınal answer Since Vcc = 20 V, RS = 3 kΩ, RB = 380 kΩ, RC = 1.2 kΩ, RE = 2.2 kΩ, RL = 911 Ω and β = 90 in the circuit in the figure, find the value of the output voltage (Vo). NOTE-1: It is within the 1 kHz mid-band frequency and the capacitors are negligible at this frequency. NOTE-2: The output impedance (r0) of the transistor will be neglected. a. 64,14 mV b. 83,88 mV c. 93,75 mV d. 74,01 mV e. 103,62 mV f. 24,67 mV g. 34,54 mV h. 49,34 mVarrow_forward1. "Given a common emiiter amplifier (Fixed BIas) with the following network: RB = 3.1k, Rc = 1k, Beta = 150, Vcc = 12V. Determine the output impedance." 1.974k ohms 1k ohms 8.621 ohms 2.7k ohms The circuit does not operate as an amplifier 6.8 ohms 3.1k ohms 2. "Given a common emiiter amplifier (Voltage Divider) with the following network: R1 = 22k, R2 = 6.8k, Rc = 1k, Re = 560, Beta = 150, Vcc = 12V. The load resistance Rl = 10k. The output impedance is ________. Note: R2 is the resistor connected to the base and ground." 1000 ohms 732 ohms 909 ohms 1245 ohms "10,000 ohms" 833 ohms 3. "Given a common emiiter amplifier (Fixed BIas) with the following network: RB = 3.1k, Rc = 1k, Beta = 150, Vcc = 12V. Determine the unloaded voltage gain." The circuit does not operate as an amplifier 205 "2,202" 220…arrow_forwardIf the multistage amplifier is driven by a 1 μV source and the last stage is loaded with an RL = 20 kΩ, determine the ac emitter resistor, re, for each stage. Given: R1 = 33 kΩ, R2 = 8.2 kΩ, RC = 3.3 kΩ, RE = 1 kΩ, Beta = 175arrow_forward
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