   # A 2.20-g sample of an unknown acid (empirical formula = C 3 H 4 O 3 ) is dissolved in 1.0 L of water. A titration required 25.0 mL of 0.500 M NaOH to react completely with all the acid present. Assuming the unknown acid has one acidic proton per molecule, what is the molecular formula of the unknown acid? ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 6, Problem 105AE
Textbook Problem
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## A 2.20-g sample of an unknown acid (empirical formula = C3H4O3) is dissolved in 1.0 L of water. A titration required 25.0 mL of 0.500 M NaOH to react completely with all the acid present. Assuming the unknown acid has one acidic proton per molecule, what is the molecular formula of the unknown acid?

Interpretation Introduction

Interpretation: To calculate the molecular formula of unknown acid

Concept Introduction: Molecular formula is a chemical formula that is a representation of total number and kinds of atoms and molecules.

### Explanation of Solution

Explanation

Record the given info

Mass of Unknown acid = 2.20g

Volume of NaOH = 25.0ml

Molarity of NaOH= 0.500M

The volume and molarity of NaOH are given along with the sample of mass as shown above.

Calculate the moles in the unknown acid

Let HA be unknown monoprotic acid

Moles of HA=25mlof0.5MNaOH=25×0.51000molNaOH

=0.0125molNaOH

The mole of the unknown monoprotic acid is calculated by plugging the values of volume and molarity of sodium hydroxide. Hence, the moles of unknown monoprotic acid is 0.0125 mol HA

Therefore, 25mlofNaOH neutralizes 1litre of acid solution which contains 2.2mmolofacid,

Hence, we can write

Molarmassofunknownacid(g/mol)=2

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