Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN: 9781305251052
Author: Michael Cummings
Publisher: Cengage Learning
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Chapter 7, Problem 17QP
Equalizing the Expression of X Chromosome Genes in Males and Females
How many Barr bodies would the following individuals have?
- a. normal male
- b. normal female
- c. Klinefelter male
- d. Turner female
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Hemophilia in humans is due to a mutation on the X chromosome. What will be the result of mating between a normal (non-carrier) female and a hemophiliac male?
A. Half of the daughters are normal and half of the sons are hemophiliacs.
B. All sons are normal and all daughters are carriers.
C. All daughters are normal and all sons are carriers.
D. Half of the children are normal and the other half are hemophiliacs; All daughters are carriers.
A geneticist determines that the order of four genes on a specific chromosome is CABD because the recombination frequencies were 35% for C-D, 24% for A-D, 23% for B-D, and 10% for A-B. What has the geneticist constructed?
A. a physical map
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Color blindness in men is controlled by a recessive gene located on the X chromosome. Can a brother and sister with color blindness have another normal brother?
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Chapter 7 Solutions
Human Heredity: Principles and Issues (MindTap Course List)
Ch. 7.6 - Prob. 1EGCh. 7.6 - Prob. 2EGCh. 7 - As outlined in this chapter, sex can be defined at...Ch. 7 - As outlined in this chapter, sex can be defined at...Ch. 7 - Prob. 1QPCh. 7 - The Human Reproductive System Discuss and compare...Ch. 7 - Prob. 3QPCh. 7 - A Survey of Human Development from Fertilization...Ch. 7 - Prob. 5QPCh. 7 - Prob. 6QP
Ch. 7 - Prob. 7QPCh. 7 - How Is Sex Determined? The absence of a Y...Ch. 7 - Prob. 9QPCh. 7 - Mutations Can Uncouple Chromosomal Sex from...Ch. 7 - Prob. 11QPCh. 7 - Mutations Can Uncouple chromosomal Sex from...Ch. 7 - Prob. 13QPCh. 7 - Sex-Influenced and Sex-Limited Traits What method...Ch. 7 - Prob. 15QPCh. 7 - Prob. 16QPCh. 7 - Equalizing the Expression of X Chromosome Genes in...Ch. 7 - Equalizing the Expression of X Chromosome Genes in...Ch. 7 - Equalizing the Expression of X Chromosome Genes in...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- The mating below shows the sex chromosome found in two parents and their resulting offspring. Use this family information to answer the following questions. Xfmr1 Y x Xfmr1 XFMR1 → XFMR1 XFMR1Y How many Barr bodies would the child have? a. 3 b. 2 c. 1 d. 0 e. Cannot be determinedarrow_forwardA. Give 7 genes located on X chromosomes and provide 2 protein products of each gene. B. Give 4 genes located on Y chromosomes and provide 2 protein products of each gene.arrow_forwardThe F1 flies described in question 1 were mated with brown-eyed flies from a true-breeding line. What phenotypes would you expect the offspring to have? (a) all with red eyes (b) all with brown eyes (c) half with red eyes and half with brown eyes (d) red-eyed females and brown-eyed males (e) brown-eyed females and red-eyed malesarrow_forward
- In a cross between a homozygous red-eyed female fruit fly and a white-eyed male fruit fly, what is the expected outcome? a. all white-eyed male offspring b. all white-eyed female offspring c. all red-eyed offspring d. half white-eyed make offspringarrow_forwardWhat are the types of gametes that can be produced by an individual with the genotype AaBb? a. Aa,Bb b. AA, aa, BB. bb c. AB, Ab, aB, ab d. AB,abarrow_forwardOne of the autosomal loci controlling eye color in fruit flies has two alleles: one for brown eyes and the other for red eyes. Fruit flies from a true-breeding line with brown eyes were crossed with flies from a true-breeding line with red eyes. The F1 flies had red eyes. What conclusion can be drawn from this experiment? (a) these alleles underwent independent assortment (b) these alleles underwent segregation (c) these genes are X-linked (d) the allele for red eyes is dominant to the allele for brown eyes (e) all the preceding are truearrow_forward
- Human females have two X chromosomes XX; males have one X and one Y chromosome XY. a. With respect to X-linked alleles, how many different types of gametes can a male produce? b. A female homozygous for an X-linked allele can produce how many types of gametes with respect to that allele? c. A female heterozygous for an X-linked allele can produce how many types of gametes with respect to that allele?arrow_forwardMatch the terms with the best description. ___ dihybrid cross a. bb ___ monohybrid cross b. AaBbAaBb ___ homozygous condition c. Aa ___ heterozygous condition d. AaAaarrow_forwardAlternative forms of the same gene are called _________ . a. gametes c. alleles b. homologous d. sister chromatidsarrow_forward
- Two normal-looking fruit flies were crossed, and, in the progeny, there were 202 females and 98 males.a. What is unusual about this result?b. Provide a genetic explanation for this anomaly.c. Provide a test of your hypothesis.arrow_forwardwhat is the likelihood that a male will inherit a sex-linked mutation on the X chromosome from his father ? A. 0% B. 25% C. 50% D. 100%arrow_forwardHemophilia is an X-linked recessive disease. A hemophilic man marries a woman who is not a carrier of the disease. (a) Draw a Punnett square showing the genotypes of their children. (b) What are the chances that their daughters will be carriers of the disease? (c) What percentage of their children are likely to have the disease?arrow_forward
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