Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
2nd Edition
ISBN: 9781305079243
Author: Steven S. Zumdahl, Susan A. Zumdahl
Publisher: Cengage Learning
bartleby

Concept explainers

bartleby

Videos

Textbook Question
Chapter 8, Problem 41E

A diagram for an open-tube manometer is shown below.

Chapter 8, Problem 41E, A diagram for an open-tube manometer is shown below. If the flask is open to the atmosphere, the , example  1

If the flask is open to the atmosphere, the mercury levels are equal. For each of the following situations where a gas is contained in the flask, calculate the pressure in the flask in torr, atmospheres, and pascals.

Chapter 8, Problem 41E, A diagram for an open-tube manometer is shown below. If the flask is open to the atmosphere, the , example  2

c. Calculate the pressures in the flask in parts a and b (in torr) if the atmospheric pressure is 635 torr.

(a)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The pressure of the gases in given two situations of manometers (a) and (b) should be determined in units of torr, atm and pascals when the manometer shows a reading of 118mm and 215mm respectively. And also calculate the pressure of the gases in given two situations of manometers (a) and (b) If the atmospheric pressure is 635 torr.

Concept Introduction:

The manometer is a devise used measure the pressure of a gas. The pressure of gas is determined by the value of ‘h’ shown by the manometer. This ‘h’-value is added or subtracted with atmospheric pressure to determine the pressure of gas.

If the flask side mercury level is decreased after the filling of gas, then the ‘h’-value will be added to atmospheric pressure to get the pressure of gas.

If the flask side mercury level is increased after the filling of gas, then the ‘h’-value will be subtracted from the atmospheric pressure to get the pressure of gas.

The pressure equivalent of ‘h’ value is,

h=1mm=1mmHg

Pressure of a substance can be stated in various units. The units of pressure are interconvertible. The relations between units of pressure are,

  • Since the unit mm Hg and the unit torr is used interchangeably.

1mmHg = 1torr

  • Conversion of 1 torr into atm is,

                     1mmHg = 1760atm 

  • The 1 mm Hg pressure in Pa unit is,

                                 1mmHg = 101325760Pa

Answer to Problem 41E

The pressure of the given gas (figure-a) in units of torr, atm and pascal are,

642 torr, 0.8447 atm, 85593 Pa

Explanation of Solution

The given ‘h’ value for the gas in manometer is 118mm. The picture of manometer shows the    flask side mercury level is increased after the filling of gas.

Hence the equation for finding the pressure of gas is,

Atmospheric pressureh(inmm)

That is,

=    (760118)mmHg

=    642mmHg

The calculated pressure is 642 mm Hg; the mm Hg and torr units are used interchangeably,

Therefore,

642mmHg = 642torr

The calculated pressure is 642mm Hg. So the pressure in atm unit is,

642mmHg = 642mmHg*1760mmHgatm 

     =      0.8447atm

The calculated pressure is 642mm Hg. So the pressure in Pa unit is,

642mmHg = 642mmHg*101325760mmHgPa

   =85593Pa

(b)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The pressure of the gases in given two situations of manometers (a) and (b) should be determined in units of torr, atm and pascals when the manometer shows a reading of 118mm and 215mm respectively. And also calculate the pressure of the gases in given two situations of manometers (a) and (b) If the atmospheric pressure is 635 torr.

Concept Introduction:

The manometer is a devise used measure the pressure of a gas. The pressure of gas is determined by the value of ‘h’ shown by the manometer. This ‘h’-value is added or subtracted with atmospheric pressure to determine the pressure of gas.

If the flask side mercury level is decreased after the filling of gas, then the ‘h’-value will be added to atmospheric pressure to get the pressure of gas.

If the flask side mercury level is increased after the filling of gas, then the ‘h’-value will be subtracted from the atmospheric pressure to get the pressure of gas.

The pressure equivalent of ‘h’ value is,

h=1mm=1mmHg

Pressure of a substance can be stated in various units. The units of pressure are interconvertible. The relations between units of pressure are,

  • Since the unit mm Hg and the unit torr is used interchangeably.

1mmHg = 1torr

  • Conversion of 1 torr into atm is,

                     1mmHg = 1760atm 

  • The 1 mm Hg pressure in Pa unit is,

                                 1mmHg = 101325760Pa

Answer to Problem 41E

The pressure of the given gas (figure-b) in units of torr, atm and pascal are,

878 torr, 1.1552 atm, 117057 Pa

Explanation of Solution

The given ‘h’ value for the gas in manometer is 118mm. The picture of manometer shows the    flask side mercury level is decreased after the filling of gas.

Hence the equation for finding the pressure of gas is,

Atmospheric pressure+h(inmm)

That is,

=   (760+118)mmHg

=   878mmHg

The calculated pressure is 878 mm Hg; the mm Hg and torr units are used interchangeably,

Therefore,

878mmHg = 878torr

The calculated pressure is 878mm Hg. So the pressure in atm unit is,

878mmHg = 878mmHg*1760mmHgatm 

     =      1.1552atm

The calculated pressure is 878mm Hg. So the pressure in Pa unit is,

878mmHg = 878mmHg*101325760mmHgPa

   =117057Pa

(c)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The pressure of the gases in given two situations of manometers (a) and (b) should be determined in units of torr, atm and pascals when the manometer shows a reading of 118mm and 215mm respectively. And also calculate the pressure of the gases in given two situations of manometers (a) and (b) If the atmospheric pressure is 635 torr.

Concept Introduction:

The manometer is a devise used measure the pressure of a gas. The pressure of gas is determined by the value of ‘h’ shown by the manometer. This ‘h’-value is added or subtracted with atmospheric pressure to determine the pressure of gas.

If the flask side mercury level is decreased after the filling of gas, then the ‘h’-value will be added to atmospheric pressure to get the pressure of gas.

If the flask side mercury level is increased after the filling of gas, then the ‘h’-value will be subtracted from the atmospheric pressure to get the pressure of gas.

The pressure equivalent of ‘h’ value is,

h=1mm=1mmHg

Pressure of a substance can be stated in various units. The units of pressure are interconvertible. The relations between units of pressure are,

  • Since the unit mm Hg and the unit torr is used interchangeably.

1mmHg = 1torr

  • Conversion of 1 torr into atm is,

                     1mmHg = 1760atm 

  • The 1 mm Hg pressure in Pa unit is,

                                 1mmHg = 101325760Pa

Answer to Problem 41E

The pressure of the given gas (figure-a) in units of torr, atm and pascal when the atmospheric pressure is 635 torr are,

517 torr, 0.8141 atm, 82496 Pa

The pressure of the given gas (figure-b) in units of torr, atm and pascal when the atmospheric pressure is 635 torr are,

753 torr, 1.1858 atm, 120154 Pa

Explanation of Solution

The pressure of the gas in given situation of manometer (a) in units of torr, atm and pascals:

The given ‘h’ value for the gas in manometer (a) is 118mm. The picture of manometer shows the    flask side mercury level is increased after the filling of gas.

Hence the equation for finding the pressure of gas is,

Atmospheric pressureh(inmm)

That is,

=   (635118)mmHg

=   517mmHg

The calculated pressure is 517 mm Hg; the mm Hg and torr units are used interchangeably,

Therefore,

517mmHg = 517torr

The calculated pressure is 517mm Hg. So the pressure in atm unit is,

517mmHg = 517mmHg*1760mmHgatm 

     =      0.8141atm

The calculated pressure is 517mm Hg. So the pressure in Pa unit is,

517mmHg = 517mmHg*101325760mmHgPa

   =82496Pa

The pressure of the gas in given situation of manometer (b) in units of torr, atm and pascals:

The given ‘h’ value for the gas in manometer is 118mm. The picture of manometer shows the    flask side mercury level is decreased after the filling of gas.

Hence the equation for finding the pressure of gas is,

Atmospheric pressure+h(inmm)

That is,

=   (635+118)mmHg

=   753mmHg

The calculated pressure is 753 mm Hg; the mm Hg and torr units are used interchangeably,

Therefore,

753mmHg = 753torr

The calculated pressure is 753 mm Hg. So the pressure in atm unit is,

753mmHg = 753mmHg*1760mmHgatm 

     =      1.1858atm

The calculated pressure is 753 mm Hg. So the pressure in Pa unit is,

753mmHg = 753mmHg*101325760mmHgPa

   =120154Pa

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Chapter 8 Solutions

Chemistry: An Atoms First Approach

Ch. 8 - Prob. 3ALQCh. 8 - Prob. 4ALQCh. 8 - Prob. 6ALQCh. 8 - Prob. 8ALQCh. 8 - Prob. 11ALQCh. 8 - Prob. 12ALQCh. 8 - Prob. 15ALQCh. 8 - Prob. 16ALQCh. 8 - Draw molecular-level views that show the...Ch. 8 - Prob. 20QCh. 8 - Prob. 21QCh. 8 - Prob. 22QCh. 8 - Prob. 23QCh. 8 - Prob. 24QCh. 8 - Prob. 25QCh. 8 - Consider two different containers, each filled...Ch. 8 - Prob. 27QCh. 8 - Prob. 28QCh. 8 - Prob. 29QCh. 8 - Prob. 30QCh. 8 - Prob. 31QCh. 8 - Prob. 32QCh. 8 - Prob. 33QCh. 8 - Prob. 34QCh. 8 - Prob. 35QCh. 8 - Prob. 36QCh. 8 - Prob. 37ECh. 8 - Prob. 38ECh. 8 - A sealed-tube manometer (as shown below) can be...Ch. 8 - Prob. 40ECh. 8 - A diagram for an open-tube manometer is shown...Ch. 8 - Prob. 42ECh. 8 - Prob. 43ECh. 8 - Prob. 44ECh. 8 - Prob. 45ECh. 8 - Prob. 46ECh. 8 - Prob. 47ECh. 8 - Prob. 48ECh. 8 - Prob. 49ECh. 8 - Prob. 50ECh. 8 - The Steel reaction vessel of a bomb calorimeter,...Ch. 8 - A 5.0-L flask contains 0.60 g O2 at a temperature...Ch. 8 - Prob. 53ECh. 8 - A person accidentally swallows a drop of liquid...Ch. 8 - A gas sample containing 1.50 moles at 25C exerts a...Ch. 8 - Prob. 56ECh. 8 - Prob. 57ECh. 8 - What will be the effect on the volume of an ideal...Ch. 8 - Prob. 59ECh. 8 - Prob. 60ECh. 8 - An ideal gas is contained in a cylinder with a...Ch. 8 - Prob. 62ECh. 8 - A sealed balloon is filled with 1.00 L helium at...Ch. 8 - Prob. 64ECh. 8 - Consider the following reaction:...Ch. 8 - A student adds 4.00 g of dry ice (solid CO2) to an...Ch. 8 - Air bags are activated when a severe impact causes...Ch. 8 - Concentrated hydrogen peroxide solutions are...Ch. 8 - In 1897 the Swedish explorer Andre tried to reach...Ch. 8 - Sulfur trioxide, SO3, is produced in enormous...Ch. 8 - A 15.0-L rigid container was charged with 0.500...Ch. 8 - An important process for the production of...Ch. 8 - Consider the reaction between 50.0 mL liquid...Ch. 8 - Urea (H2NCONH2) is used extensively as a nitrogen...Ch. 8 - Prob. 75ECh. 8 - Prob. 76ECh. 8 - Prob. 77ECh. 8 - A compound has the empirical formula CHCl. A...Ch. 8 - Prob. 79ECh. 8 - Given that a sample of air is made up of nitrogen,...Ch. 8 - Prob. 81ECh. 8 - Prob. 82ECh. 8 - Prob. 83ECh. 8 - Prob. 84ECh. 8 - Consider the flasks in the following diagram. What...Ch. 8 - Consider the flask apparatus in Exercise 85, which...Ch. 8 - Prob. 87ECh. 8 - At 0C a 1.0-L flask contains 5.0 102 mole of N2,...Ch. 8 - Prob. 89ECh. 8 - A tank contains a mixture of 52.5 g oxygen gas and...Ch. 8 - Prob. 91ECh. 8 - Helium is collected over water at 25C and 1.00 atm...Ch. 8 - At elevated temperatures, sodium chlorate...Ch. 8 - Xenon and fluorine will react to form binary...Ch. 8 - Methanol (CH3OH) can be produced by the following...Ch. 8 - In the Mthode Champenoise, grape juice is...Ch. 8 - Hydrogen azide, HN3, decomposes on heating by the...Ch. 8 - Prob. 98ECh. 8 - Some very effective rocket fuels are composed of...Ch. 8 - The oxides of Group 2A metals (symbolized by M...Ch. 8 - Prob. 101ECh. 8 - Prob. 102ECh. 8 - Prob. 103ECh. 8 - Prob. 104ECh. 8 - Prob. 105ECh. 8 - Prob. 106ECh. 8 - Prob. 107ECh. 8 - Prob. 108ECh. 8 - Prob. 109ECh. 8 - Prob. 110ECh. 8 - Prob. 111ECh. 8 - Prob. 112ECh. 8 - Prob. 113ECh. 8 - Prob. 114ECh. 8 - Prob. 115ECh. 8 - Prob. 116ECh. 8 - Prob. 117ECh. 8 - Prob. 118ECh. 8 - Prob. 119ECh. 8 - Prob. 120ECh. 8 - Prob. 121ECh. 8 - Prob. 122ECh. 8 - Prob. 123AECh. 8 - At STP, 1.0 L Br2 reacts completely with 3.0 L F2,...Ch. 8 - Prob. 125AECh. 8 - A 2.747g sample of manganese metal is reacted with...Ch. 8 - Prob. 127AECh. 8 - Cyclopropane, a gas that when mixed with oxygen is...Ch. 8 - The nitrogen content of organic compounds can be...Ch. 8 - Prob. 130AECh. 8 - A 15.0L tank is filled with H2 to a pressure of...Ch. 8 - A spherical glass container of unknown volume...Ch. 8 - Prob. 133AECh. 8 - A 20.0L stainless steel container at 25C was...Ch. 8 - Metallic molybdenum can be produced from the...Ch. 8 - Prob. 136AECh. 8 - Prob. 137AECh. 8 - One of the chemical controversies of the...Ch. 8 - An organic compound contains C, H, N, and O....Ch. 8 - Prob. 140AECh. 8 - The total volume of hydrogen gas needed to fill...Ch. 8 - Prob. 142AECh. 8 - Prob. 143CWPCh. 8 - Prob. 144CWPCh. 8 - A certain flexible weather balloon contains helium...Ch. 8 - Prob. 146CWPCh. 8 - A 20.0L nickel container was charged with 0.859...Ch. 8 - Consider the unbalanced chemical equation below:...Ch. 8 - Prob. 149CWPCh. 8 - Which of the following statements is(are) true? a....Ch. 8 - A chemist weighed out 5.14 g of a mixture...Ch. 8 - A mixture of chromium and zinc weighing 0.362 g...Ch. 8 - Prob. 153CPCh. 8 - You have an equimolar mixture of the gases SO2 and...Ch. 8 - Methane (CH4) gas flows into a combustion chamber...Ch. 8 - Prob. 156CPCh. 8 - Prob. 157CPCh. 8 - Prob. 158CPCh. 8 - You have a helium balloon at 1.00 atm and 25C. You...Ch. 8 - Prob. 160CPCh. 8 - You are given an unknown gaseous binary compound...Ch. 8 - Prob. 162CPCh. 8 - Calculate w and E when 1 mole of a liquid is...Ch. 8 - The preparation of NO2(g) from N2(g) and O2(g) is...Ch. 8 - In the presence of nitric acid, UO2+ undergoes a...Ch. 8 - Silane, SiH4, is the silicon analogue of methane,...Ch. 8 - Prob. 167IPCh. 8 - Prob. 168IPCh. 8 - Prob. 169MP
Knowledge Booster
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
    Recommended textbooks for you
  • Introductory Chemistry: An Active Learning Approa...
    Chemistry
    ISBN:9781305079250
    Author:Mark S. Cracolice, Ed Peters
    Publisher:Cengage Learning
    Chemistry: An Atoms First Approach
    Chemistry
    ISBN:9781305079243
    Author:Steven S. Zumdahl, Susan A. Zumdahl
    Publisher:Cengage Learning
    Chemistry
    Chemistry
    ISBN:9781305957404
    Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
    Publisher:Cengage Learning
  • Chemistry
    Chemistry
    ISBN:9781133611097
    Author:Steven S. Zumdahl
    Publisher:Cengage Learning
    Chemistry: Principles and Practice
    Chemistry
    ISBN:9780534420123
    Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
    Publisher:Cengage Learning
    Chemistry for Engineering Students
    Chemistry
    ISBN:9781337398909
    Author:Lawrence S. Brown, Tom Holme
    Publisher:Cengage Learning
  • Introductory Chemistry: An Active Learning Approa...
    Chemistry
    ISBN:9781305079250
    Author:Mark S. Cracolice, Ed Peters
    Publisher:Cengage Learning
    Chemistry: An Atoms First Approach
    Chemistry
    ISBN:9781305079243
    Author:Steven S. Zumdahl, Susan A. Zumdahl
    Publisher:Cengage Learning
    Chemistry
    Chemistry
    ISBN:9781305957404
    Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
    Publisher:Cengage Learning
    Chemistry
    Chemistry
    ISBN:9781133611097
    Author:Steven S. Zumdahl
    Publisher:Cengage Learning
    Chemistry: Principles and Practice
    Chemistry
    ISBN:9780534420123
    Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
    Publisher:Cengage Learning
    Chemistry for Engineering Students
    Chemistry
    ISBN:9781337398909
    Author:Lawrence S. Brown, Tom Holme
    Publisher:Cengage Learning
    Step by Step Stoichiometry Practice Problems | How to Pass ChemistryMole Conversions Made Easy: How to Convert Between Grams and Moles; Author: Ketzbook;https://www.youtube.com/watch?v=b2raanVWU6c;License: Standard YouTube License, CC-BY