Chapter 8.1, Problem 11PSA

a

To determine

To Calculate:The geometric mean of the given pair of extremes i.e. 4 and 25.

Answer to Problem 11PSA

The geometric mean of the given pair of extremes is 10

Explanation of Solution

Given information

Pair of extremes is 4 and 25

Formula used

Geometric mean = square root of product of extremes

Calculation

Geometric mean of 4 and 25

  $\begin{array}{l}=\sqrt{4\times 25}\\ =\sqrt{100}\\ =10\end{array}$

b

To determine

To Calculate:The geometric mean of the given pair of extremes i.e. 3 and 5.

Answer to Problem 11PSA

The geometric mean of the given pair of extremes is $\sqrt{15}$

Explanation of Solution

Given information

Pair of extremes is 3 and 5

Formula used

Geometric mean = square root of product of extremes

Calculation

Geometric mean of 3 and 5

  $\begin{array}{l}=\sqrt{3\times 5}\\ =\sqrt{15}\end{array}$

c

To determine

To Calculate:The geometric mean of the given pair of extremes i.e. a and b.

Answer to Problem 11PSA

The geometric mean of the given pair of extremes is $\sqrt{ab}$

Explanation of Solution

Given information

Pair of extremes as a and b

Formula used

Geometric mean = square root of product of extremes

Calculation

Geometric mean of a and b

  $\begin{array}{l}=\sqrt{a\times b}\\ =\sqrt{ab}\end{array}$