Chapter 8.4, Problem 13PSB

To determine

Prove the given statement.

Answer to Problem 13PSB

Proved $\frac{AH}{DG}=\frac{AC}{DF}$ .

Explanation of Solution

Given information:

The ratio of corresponding altitudes of similar triangles is equal to the ratio of any pair of corresponding sides of the triangles.

Calculation:

As per the statement the figures are,

  

  $\begin{array}{l}\Delta ABC\cong \Delta DEF\\ allangles\Delta AHCand\Delta DGFaresame\\ Therefore,\\ \Delta AHC\cong \Delta DGF\\ \frac{AH}{DG}=\frac{AC}{DF}\end{array}$

Hence, proved $\frac{AH}{DG}=\frac{AC}{DF}$ .