Chapter 8.4, Problem 14PSB

To determine

Find the coordinate of point $P$ .

Answer to Problem 14PSB

  $P\left(0,12\right)$

Explanation of Solution

Given information:

  

Calculation:

Consider the given figure and find the slope of the lower line,

  $\begin{array}{l}slope=\frac{\Delta y}{\Delta x}=\frac{8-0}{0-\left(-6\right)}\\ =\frac{8}{6}=\frac{4}{3}\end{array}$

Both the line are parallel so the slope also be same,

The $x$ coordinate of point $P$ is $0$ now find $y-coordinate$ ,

  $\begin{array}{l}y-coordinate=\frac{4}{3}=\frac{y-0}{0-\left(-9\right)}\\ y-coordinate=\frac{4}{3}=\frac{y}{9}\\ y=\frac{36}{3}=12\end{array}$

Hence, the coordinates of point $P\left(0,12\right)$ .