A new method for the analysis of mercury was in an ore sample was tested and obtained the following data: Trial % Hg 1 12.76 2 12.57 3 12.72 4 12.79 5 12.76 Average: 12.72 St. Deviation: 0.08746 The standard method for mercury analysis was also used to test the ore. Is the mean value of the new method significantly different from the mean value of the accepted value at the 95% confidence interval? You may assume the standard deviations are the same. Accepted Method Results # of samples = 6 Average = 12.63% Hg Standard deviation = 0.053
A new method for the analysis of mercury was in an ore sample was tested and obtained the following data: Trial % Hg 1 12.76 2 12.57 3 12.72 4 12.79 5 12.76 Average: 12.72 St. Deviation: 0.08746 The standard method for mercury analysis was also used to test the ore. Is the mean value of the new method significantly different from the mean value of the accepted value at the 95% confidence interval? You may assume the standard deviations are the same. Accepted Method Results # of samples = 6 Average = 12.63% Hg Standard deviation = 0.053
Chapter7: Statistical Data Treatment And Evaluation
Section: Chapter Questions
Problem 7.13QAP
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Question
A new method for the analysis of mercury was in an ore sample was tested and obtained the following data:
Trial |
% Hg |
1 |
12.76 |
2 |
12.57 |
3 |
12.72 |
4 |
12.79 |
5 |
12.76 |
Average: 12.72
St. Deviation: 0.08746
The standard method for mercury analysis was also used to test the ore. Is the mean value of the new method significantly different from the mean value of the accepted value at the 95% confidence interval? You may assume the standard deviations are the same.
Accepted Method Results |
# of samples = 6 |
Average = 12.63% Hg |
Standard deviation = 0.053 |
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