ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5
ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5
2nd Edition
ISBN: 9780393664034
Author: KARTY
Publisher: NORTON
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Chapter 10, Problem 10.57P
Interpretation Introduction

(a)

Interpretation:

The complete and detailed mechanism with the major product formed in the given reaction is to be drawn.

Concept introduction:

Vinylic halides undergo E2 reactions to produce an alkyne. When vinylic halides are treated with a strong base such as NaNH2, the strong base abstracts a weakly acidic hydrogen atom in vinylic halide. At the same time, the bond between the other doubly bonded carbon atom and the halogen atom breaks to form an alkyne. One equivalent of the base is needed if the vinylic halide has only one hydrogen atom attached to one of the doubly bonded carbon atoms. This results in the formation of an internal alkyne. Two equivalents of base are used if the vinylic halide has two hydrogen atom attached to both doubly bonded carbon atoms. This results in the formation of a terminal alkyne.

Interpretation Introduction

(b)

Interpretation:

The complete and detailed mechanism with the major product formed in the given reaction is to be drawn.

Concept introduction:

Vinylic halides undergo E2 reactions to produce an alkyne. When vinylic halides are treated with a strong base such as NaNH2, the strong base abstracts a weakly acidic hydrogen atom in vinylic halide. At the same time, the bond between the other doubly bonded carbon atom and the halogen atom breaks to form an alkyne. One equivalent of the base is needed if the vinylic halide has only one hydrogen atom attached to one of the doubly bonded carbon atoms. This results in the formation of an internal alkyne. Two equivalents of base are used if the vinylic halide has two hydrogen atom attached to both doubly bonded carbon atoms. This results in the formation of a terminal alkyne.

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Chapter 10 Solutions

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5

Ch. 10 - Prob. 10.11PCh. 10 - Prob. 10.12PCh. 10 - Prob. 10.13PCh. 10 - Prob. 10.14PCh. 10 - Prob. 10.15PCh. 10 - Prob. 10.16PCh. 10 - Prob. 10.17PCh. 10 - Prob. 10.18PCh. 10 - Prob. 10.19PCh. 10 - Prob. 10.20PCh. 10 - Prob. 10.21PCh. 10 - Prob. 10.22PCh. 10 - Prob. 10.23PCh. 10 - Prob. 10.24PCh. 10 - Prob. 10.25PCh. 10 - Prob. 10.26PCh. 10 - Prob. 10.27PCh. 10 - Prob. 10.28PCh. 10 - Prob. 10.29PCh. 10 - Prob. 10.30PCh. 10 - Prob. 10.31PCh. 10 - Prob. 10.32PCh. 10 - Prob. 10.33PCh. 10 - Prob. 10.34PCh. 10 - Prob. 10.35PCh. 10 - Prob. 10.36PCh. 10 - Prob. 10.37PCh. 10 - Prob. 10.38PCh. 10 - Prob. 10.39PCh. 10 - Prob. 10.40PCh. 10 - Prob. 10.41PCh. 10 - Prob. 10.42PCh. 10 - Prob. 10.43PCh. 10 - Prob. 10.44PCh. 10 - Prob. 10.45PCh. 10 - Prob. 10.46PCh. 10 - Prob. 10.47PCh. 10 - Prob. 10.48PCh. 10 - Prob. 10.49PCh. 10 - Prob. 10.50PCh. 10 - Prob. 10.51PCh. 10 - Prob. 10.52PCh. 10 - Prob. 10.53PCh. 10 - Prob. 10.54PCh. 10 - Prob. 10.55PCh. 10 - Prob. 10.56PCh. 10 - Prob. 10.57PCh. 10 - Prob. 10.58PCh. 10 - Prob. 10.59PCh. 10 - Prob. 10.60PCh. 10 - Prob. 10.61PCh. 10 - Prob. 10.62PCh. 10 - Prob. 10.63PCh. 10 - Prob. 10.64PCh. 10 - Prob. 10.65PCh. 10 - Prob. 10.66PCh. 10 - Prob. 10.67PCh. 10 - Prob. 10.68PCh. 10 - Prob. 10.69PCh. 10 - Prob. 10.70PCh. 10 - Prob. 10.71PCh. 10 - Prob. 10.72PCh. 10 - Prob. 10.73PCh. 10 - Prob. 10.74PCh. 10 - Prob. 10.1YTCh. 10 - Prob. 10.2YTCh. 10 - Prob. 10.3YTCh. 10 - Prob. 10.4YTCh. 10 - Prob. 10.5YTCh. 10 - Prob. 10.6YTCh. 10 - Prob. 10.7YTCh. 10 - Prob. 10.8YTCh. 10 - Prob. 10.9YTCh. 10 - Prob. 10.10YTCh. 10 - Prob. 10.11YTCh. 10 - Prob. 10.12YTCh. 10 - Prob. 10.13YTCh. 10 - Prob. 10.14YTCh. 10 - Prob. 10.15YTCh. 10 - Prob. 10.16YTCh. 10 - Prob. 10.17YTCh. 10 - Prob. 10.18YTCh. 10 - Prob. 10.19YT
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