Modern Physics
Modern Physics
2nd Edition
ISBN: 9780805303087
Author: Randy Harris
Publisher: Addison Wesley
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Chapter 10, Problem 62E

(a)

To determine

The comparison for the equation 10.11 evaluated at room temperature for a silicon band gap of 1.1eV and for a typical donor-state/conduction band of 0.05eV .

(b)

To determine

Whether the results suggest that minority carriers bumped up from donor levels should outnumber minority carriers created by thermal excitation across the whole 1.1eV gap.

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Students have asked these similar questions
For silicon at T = 300 K with donor density N_D = 1 * 10^9 cm^{-3}​ and acceptor density N_A = 0, calculate the equilibrium hole concentration in cm^{-3}. Values within 5% error will be considered correct.
For silicon at T = 500 K with donor density N_D = 5* 10^{13} cm^ and acceptor density N_A = 0 calculate the equilibrium hole concentration in cm^{-3}. In this problem, you can assume the bandgap energy and effective masses are independent of temperature and use the room temperature values for them. Values within 5% error will be considered correct.
Consider a n-type Si crystal at room temperature (300K) doped with 6 x1016 cm-3 arsenic impurity atoms and with certain number of shallowholes. Find out the equilibrium electron concentration, hole concentrationand Fermi level EF with respect to Ei, and the conduction band edge EC.For Si at 300K, the value of ni is 1.45 x 1010 cm-3 and k = 1.38 x 10-23 J/K,1eV = 1.60 x 10-19J. The band gap energy, Eg, of Si is 1.2eV.Solution:n @ Nd = 6 x 1016 cm-3.In equilibrium condition, hole concentration = 3.5 x 103 cm-3.EF – EI = 0.396eVEC – EF = 0.164eV.

Chapter 10 Solutions

Modern Physics

Ch. 10 - Prob. 11CQCh. 10 - In the boron atom, the single 2p electron does not...Ch. 10 - Prob. 13CQCh. 10 - Prob. 14CQCh. 10 - Prob. 15CQCh. 10 - Prob. 16CQCh. 10 - Prob. 17CQCh. 10 - Prob. 18CQCh. 10 - Prob. 19CQCh. 10 - Prob. 20CQCh. 10 - Prob. 21CQCh. 10 - Prob. 22CQCh. 10 - In a buckyball three of the bonds around each...Ch. 10 - Prob. 24CQCh. 10 - Prob. 25ECh. 10 - Prob. 26ECh. 10 - Prob. 27ECh. 10 - Prob. 28ECh. 10 - Prob. 29ECh. 10 - Prob. 30ECh. 10 - Prob. 31ECh. 10 - Prob. 32ECh. 10 - Prob. 33ECh. 10 - Prob. 34ECh. 10 - By expanding an arbitrary U(x) in a power series...Ch. 10 - Prob. 36ECh. 10 - Prob. 37ECh. 10 - Prob. 38ECh. 10 - Prob. 39ECh. 10 - Prob. 40ECh. 10 - Prob. 41ECh. 10 - Prob. 42ECh. 10 - Prob. 43ECh. 10 - As noted in Example 10.2, the HD molecule differs...Ch. 10 - Prob. 45ECh. 10 - Prob. 46ECh. 10 - Prob. 47ECh. 10 - Prob. 48ECh. 10 - Prob. 49ECh. 10 - Prob. 50ECh. 10 - Prob. 51ECh. 10 - Prob. 52ECh. 10 - Prob. 53ECh. 10 - Prob. 54ECh. 10 - Carry out the integration indicated in equation...Ch. 10 - Prob. 56ECh. 10 - Prob. 57ECh. 10 - Prob. 58ECh. 10 - Prob. 59ECh. 10 - Prob. 60ECh. 10 - Prob. 61ECh. 10 - Prob. 62ECh. 10 - Prob. 63ECh. 10 - Prob. 64ECh. 10 - Prob. 65ECh. 10 - Prob. 66ECh. 10 - Prob. 67ECh. 10 - Prob. 68ECh. 10 - Prob. 69ECh. 10 - Prob. 70ECh. 10 - Prob. 71ECh. 10 - Prob. 72ECh. 10 - Prob. 73ECh. 10 - Prob. 74ECh. 10 - The magnetic field at the surface of a long Wire...Ch. 10 - Prob. 76ECh. 10 - Prob. 77CECh. 10 - Prob. 78CECh. 10 - Prob. 79CE
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