Modern Physics
2nd Edition
ISBN: 9780805303087
Author: Randy Harris
Publisher: Addison Wesley
expand_more
expand_more
format_list_bulleted
Question
Chapter 10, Problem 63E
To determine
The amount of energy required to free a donor electron
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
What is the probability that, at a temperature of T = 300 K, an electron will jump across the energy gap Eg (= 5.5 eV) in a diamond that has a mass equal to the mass of Earth? Use the molar mass of carbon in Appendix F; assume that in diamond there is one valence electron per carbon atom.
In a silicon lattice, where should you look if you want to find (a) a conduction electron, (b) a valence electron, and (c) an electron associated with the 2p subshell of the isolated silicon atom?
When a photon enters the depletion zone of a p-n junction, the photon can scatter from the valence electrons there, transferring part of its energy to each electron, which then jumps to the conduction band. Thus, the photon creates electron–hole pairs. For this reason, the junctions are often used as light detectors, especially in the x-ray and gamma-ray regions of the electromagnetic spectrum. Suppose a single 662 keV gamma-ray photon transfers its energy to electrons in multiple scattering events inside a semiconductor with an energy gap of 1.1 eV, until all the energy is transferred. Assuming that each electron jumps the gap from the top of the valence band to the bottom of the conduction band, find the number of electron – hole pairs created by the process.
Chapter 10 Solutions
Modern Physics
Ch. 10 - Prob. 1CQCh. 10 - Prob. 2CQCh. 10 - Prob. 3CQCh. 10 - Of N2,O2 , and F2 , none has an electric dipole...Ch. 10 - It takes less energy to dissociate a diatomic...Ch. 10 - Prob. 6CQCh. 10 - Prob. 7CQCh. 10 - Prob. 8CQCh. 10 - Prob. 9CQCh. 10 - Prob. 10CQ
Ch. 10 - Prob. 11CQCh. 10 - In the boron atom, the single 2p electron does not...Ch. 10 - Prob. 13CQCh. 10 - Prob. 14CQCh. 10 - Prob. 15CQCh. 10 - Prob. 16CQCh. 10 - Prob. 17CQCh. 10 - Prob. 18CQCh. 10 - Prob. 19CQCh. 10 - Prob. 20CQCh. 10 - Prob. 21CQCh. 10 - Prob. 22CQCh. 10 - In a buckyball three of the bonds around each...Ch. 10 - Prob. 24CQCh. 10 - Prob. 25ECh. 10 - Prob. 26ECh. 10 - Prob. 27ECh. 10 - Prob. 28ECh. 10 - Prob. 29ECh. 10 - Prob. 30ECh. 10 - Prob. 31ECh. 10 - Prob. 32ECh. 10 - Prob. 33ECh. 10 - Prob. 34ECh. 10 - By expanding an arbitrary U(x) in a power series...Ch. 10 - Prob. 36ECh. 10 - Prob. 37ECh. 10 - Prob. 38ECh. 10 - Prob. 39ECh. 10 - Prob. 40ECh. 10 - Prob. 41ECh. 10 - Prob. 42ECh. 10 - Prob. 43ECh. 10 - As noted in Example 10.2, the HD molecule differs...Ch. 10 - Prob. 45ECh. 10 - Prob. 46ECh. 10 - Prob. 47ECh. 10 - Prob. 48ECh. 10 - Prob. 49ECh. 10 - Prob. 50ECh. 10 - Prob. 51ECh. 10 - Prob. 52ECh. 10 - Prob. 53ECh. 10 - Prob. 54ECh. 10 - Carry out the integration indicated in equation...Ch. 10 - Prob. 56ECh. 10 - Prob. 57ECh. 10 - Prob. 58ECh. 10 - Prob. 59ECh. 10 - Prob. 60ECh. 10 - Prob. 61ECh. 10 - Prob. 62ECh. 10 - Prob. 63ECh. 10 - Prob. 64ECh. 10 - Prob. 65ECh. 10 - Prob. 66ECh. 10 - Prob. 67ECh. 10 - Prob. 68ECh. 10 - Prob. 69ECh. 10 - Prob. 70ECh. 10 - Prob. 71ECh. 10 - Prob. 72ECh. 10 - Prob. 73ECh. 10 - Prob. 74ECh. 10 - The magnetic field at the surface of a long Wire...Ch. 10 - Prob. 76ECh. 10 - Prob. 77CECh. 10 - Prob. 78CECh. 10 - Prob. 79CE
Knowledge Booster
Similar questions
- Calculate No(E), the density of occupied states, for copper atT = 1000 K for an energy E of (a) 4.00 eV, (b) 6.75 eV, (c) 7.00 eV,(d) 7.25 eV, and (e) 9.00 eV..The Fermi energy for copper is 7.00 eVarrow_forwardDiscuss the failure and Success of Classical free electron theory? Differentiate between Conductor, Insulator and Semiconductor on the basis of Conduction and valence band?arrow_forwardWhat mass of phosphorus is needed to dope 1.0 g of silicon so that the number density of conduction electrons in the silicon is increased by a multiply factor of 106 from the 10^16 m-3 in pure silicon.arrow_forward
- Assume that the total volume of a metal sample is the sumof the volume occupied by the metal ions making up the lattice andthe (separate) volume occupied by the conduction electrons. Thedensity and molar mass of sodium (a metal) are 971 kg/m3 and 23.0g/mol, respectively; assume the radius of the Na+ ion is 98.0 pm. (a)What percent of the volume of a sample of metallic sodium is occupiedby its conduction electrons? (b) Carry out the same calculationfor copper, which has density, molar mass, and ionic radius of8960 kg/m3, 63.5 g/mol, and 135 pm, respectively. (c) For which ofthese metals do you think the conduction electrons behave morelike a free-electron gas?arrow_forwardIs it feasible to describe the distinction between a conductor and an insulator using a semiconductor as an example? Why not use a graph to explain the arguments you're making?arrow_forwardFor a solid metal having a Fermi energy of 8.500 eV, what is the probability, at room temperature, that a state having an energy of 8.520 eV is occupied by an electron?arrow_forward
- Since the Fermi energy level of zinc is EF = 9.47 eV, what is the number of electrons per unit energy per unit volume at this energy level? Since the resistivity of zinc is 5.90 x 10^-8 ohm.m, calculate the average time interval between collisions of electrons.arrow_forwardTo obtain the value of an unknown electrical charge, a group performed an experiment. From the graph of the electric potential (voltage) V in volts, as a function of the inverse distance (1/r) in m^-1, the group obtained an angular coefficient 6838 Nm^2/C by the linear equation of the best straight line. Knowing that V=(kq)/r, calculate the value of the electric charge, in nC (nanocoulomb), from the slope provided by the best line. Round the answer to a whole number. Use: k = 8.9876 x 10^9 N⋅m^2⋅C^−2arrow_forwardAt what temperature do 1.30% of the conduction electrons in lithium (a metal) have energies greater than the Fermi energy EF, which is 4.70 eV?arrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
- Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage LearningGlencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-Hill
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning
Glencoe Physics: Principles and Problems, Student...
Physics
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Glencoe/McGraw-Hill