Chapter 12, Problem 12.65AP

a.

Interpretation Introduction

Interpretation:

Product formed when below alcohol is oxidized in presence of K₂Cr₂O₇ has to be determined

  ${\text{CH}}_{\text{3}}{{\text{(CH}}_{\text{2}}\text{)}}_{\text{6}}{\text{CH}}_{\text{2}}\text{OH}$

Concept introduction:

Oxidation of alcohol:

Duringoxidation of alcohol, the number of $\text{C-O}$ bonds gets increased on product side and $\text{C-H}$ bond gets decreased on reactant side. In the oxidation reaction, reaction takes place between carbon attached to hydrogen atom and carbon attached to $\text{OH}$ group and finally C-O bond is formed leading to ${\text{H}}_{\text{2}}$ removal from the reactant. Oxidation of an alcohol gives different products dependingupon the type of alcohols and reagents take part in a reaction. Oxidation of alcohols give carbonyl group in the product side. In a primary alcohol, among the two $\text{C-H}$ bonds present, the first $\text{C-H}$ bond gets oxidized into aldehyde group and then further it gets oxidized into carboxylic acid group. In case of the secondary alcohol, only the one $\text{C-H}$ bond present is oxidized into ketones. For tertiary alcohol, there are no hydrogen atoms presentand therefore, tertiary alcohols are not been able to beoxidized.

b.

Interpretation Introduction

Interpretation:

Product formed when below alcohol is oxidized in presence of K₂Cr₂O₇ has to be determined.

  ${{\text{(CH}}_{\text{3}}{\text{CH}}_{\text{2}}\text{)}}_2\text{CHOH}$

Concept introduction:

Refer to part ‘a.’.

c.

Interpretation Introduction

Interpretation:

Product formed when below alcohol is oxidized in presence of K₂Cr₂O₇ has to be determined.

Concept introduction:

Refer to part ‘a.’.