GENETICS(LL)-W/CONNECT >CUSTOM<
GENETICS(LL)-W/CONNECT >CUSTOM<
6th Edition
ISBN: 9781260571561
Author: HARTWELL
Publisher: MCG CUSTOM
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Chapter 12, Problem 8P

About 2000 G bands are visible in a high-resolution karyotype of the 3 billion base pairs in the haploid human genome. If the genome contains about 27,000 genes, about how many genes would be removed by a deletion of DNA that could be detected by karyotype analysis?

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Although DNA transposons are abundant in the genomes of multicellular eukaryotes, class 1 elements usually make up the largest fraction of very large genomes such as those from humans (~2500 Mb), maize (~2500 Mb), and barley (~5000 Mb). Given what you know about class 1 and class 2 elements, what is it about their distinct mechanisms of transposition that would account for this consistent difference in abundance?
Using a laser beam, you isolated several R bands from human chromosomes. Answer the following questions What kinds of genes are present in R bands? Which isochors do you expect to be present in the R band? What class of interspersed repeats will be present in R bands? What class of tandem repeats do you expect to find in RG bands? Would you expect to find telomere sequences in some R bands?
A diploid (ie, contains TWO sets of chromosomes) organisms with a 45,000-kb haploid (counts only one set of its chromosomes) genome contains 21% G residues. Calculate the number of A, C, G< and T residues in the DNA of each cell in this organism.  Can you help explain why this is the answer, thank you! Answer:  Since the haploid genome contains 21% G, it must contain 21% C (Because G=C) and 58%  A + T, or 29% A and 29% T.  Each cell is a diploid, containing 90,000 kb or 9x10^7 bases.  Therefore,  A=T = (0.29)(9x10^7) = 2.61 x 10^7 bases and G=C=(0.21)(9x10^7) = 1.89x10^7 bases.

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