Genetics: From Genes to Genomes, 5th edition
5th Edition
ISBN: 9780073525310
Author: Leland H. Hartwell, Michael L. Goldberg, Janice A. Fischer, Leroy Hood, Charles F. Aquadro
Publisher: McGraw-Hill Education
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Chapter 13, Problem 18P
Summary Introduction
To determine:
Whether the Pyr+Arg+exconjugants are also Xyl+ and Mal+.
Introduction:
Autotrophs are the organisms that require a specific type of nutrients like amino acid or any other substrate in the medium. These organisms cannot grow in the absence of such nutrients and cannot synthesize it through any
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An Hfr strain that is leuA+ and thiL+ was mixed with a strain thatis leuA− and thiL−. In the data points shown in the following graph,the conjugation was interrupted at different time points, and thepercentage of recombinants for each gene was determined bystreaking on a medium that lacked either leucine or thiamine.What is the map distance (in minutes) between these two genes?
An Hfr strain that is leuA+ and thiL+ was mixed with a strain thatis leuA− and thiL−. In the data points shown in the following graph,the conjugation was interrupted at different time points, and thepercentage of recombinants for each gene was determined bystreaking on a medium that lacked either leucine or thiamine.What information do you know based on the question and your understanding of the topic?
When the interrupted mating technique was used withfive different strains of Hfr bacteria, the following orders ofgene entry and recombination were observed. On the basisof these data, draw a map of the bacterial chromosome.Do the data support the concept of circularity?HfrStrain Order1 T C H R O2 H R O M B3 M O R H C4 M B A K T5 C T K A B
Chapter 13 Solutions
Genetics: From Genes to Genomes, 5th edition
Ch. 13 - Choose the phrase from the right column that best...Ch. 13 - Prob. 2PCh. 13 - Now that the sequence of the entire E. coli K12...Ch. 13 - Bacterial genomes such as that of E. coli...Ch. 13 - List at least three features of eukaryotic genomes...Ch. 13 - Describe a mechanism by which a gene could move...Ch. 13 - High salt concentrations tend to cause protein...Ch. 13 - Prob. 8PCh. 13 - A liquid culture of E. coli at a concentration of...Ch. 13 - Pick out the medium i, ii, iii, or iv onto which...
Ch. 13 - Prob. 11PCh. 13 - In two isolates one is resistant to ampicillin,...Ch. 13 - E. coli cells usually have only one copy of the F...Ch. 13 - In E. coli, the genes purC and pyrB are located...Ch. 13 - DNA sequencing of the entire H. influenzae genome...Ch. 13 - Genes encoding toxins are often located on...Ch. 13 - a. You want to perform an interrupted-mating...Ch. 13 - Prob. 18PCh. 13 - One issue with interrupted-mating experiments such...Ch. 13 - Prob. 20PCh. 13 - Starting with an F- strain that was prototrophic...Ch. 13 - You can carry out matings between an Hfr and F...Ch. 13 - Genome sequences show that some pathogenic...Ch. 13 - Generalized and specialized transduction both...Ch. 13 - Prob. 25PCh. 13 - Prob. 26PCh. 13 - Prob. 27PCh. 13 - The sequence at one end of one strand of the...Ch. 13 - Prob. 29PCh. 13 - Suppose that you could obtain radioactively...
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- A particular Hfr strain normally transmits the pro+marker as the last one in conjugation. In a cross of thisstrain with an F− strain, some pro+ recombinants are recovered early in the mating process. When these pro+cells are mixed with F−cells, the majority of the F− cellsare converted into pro+ cells that also carry the F factor.Explain these results.arrow_forwardFor each genotype in the table below, determine whether or not functional B-gal will be produced in the presence or absence of the inducer. Write a plus (+) if B-gal is produced or a minus (-) if it is not. ma Chromosome F' lac (plasmid) - Inducer + Inducer ---- --- --- I*O*Z I*O°Z+ I*O*Z* I* = wildtype repressor |- - no functional repressor produced O* - wildtype operator OC = operator mutation prevents repressor from binding %3Darrow_forwardA cross was performed between a yeast strain that requires methionine and lysine for growth (met− lys−)and another yeast strain, which is met+ lys+. One hundred asci were dissected, and colonies were grownfrom the four spores in each ascus. Cells from thesecolonies were tested for their ability to grow on petriplates containing either minimal medium (min), min+ lysine (lys), min + methionine (met), or min + lys+ met. The asci could be divided into two groupsbased on this analysis:Group 1: In 89 asci, cells from two of the four spore colonies couldgrow on all four kinds of media, while the other two spore coloniescould grow only on min + lys + met.Group 2: In 11 asci, cells from one of the four spore colonies couldgrow on all four kinds of petri plates. Cells from a second one ofthe four spore colonies could grow only on min + lys plates andon min + lys + met plates. Cells from a third of the four sporecolonies could only grow on min + met plates and on min + lys+ met. Cells from the…arrow_forward
- Three different Hfr donor strains are mixed with separate samples of an F− strain, and the following mapping data are provided from studies of interrupted conjugation: Appearance of genes in F − cells Hfr1: Genes b+ d+ c+ f+ g+ Time* 3 5 16 27 59 Hfr2: Genes e+ f+ c+ d+ b+ Time 6 24 35 46 48 Hfr3: Genes d+ c+ f+ e+ g+ Time 4 15 26 44 58 Construct a genetic map for these genes, indicating their order on the bacterial chromosome and the distances between them.arrow_forwardThree different Hfr donor strains are mixed with separate samples of an F strain, and the following mapping data are provided from studies of interrupted conjugation: Appearance of genes in F cells Hfr1: Genes b* d* c* f* g* Time* 3 16 27 59 Hfr2: Genes e* f* c* d* b+ Time 6 24 35 46 48 Hfr3: Genes d* c* f* e+ g* Time 4 15 26 44 58 Construct a genetic map for these genes, indicating their order on the bacterial chromosome and the distances between them.arrow_forwardAn Hfrstrain that is a *b*c*d* e*f* g *h* is mated with an F strain that is a b e d e f gh. The mating is interrupted at 5 minutes interval, and the genotypes of the F recombinants are determined. The results obtained are tabulated in Table 2. Draw the map of the Hfrchromosome and indicate the position of the origin of transfer, the direction of the transfer and the minutes between genes. Table 2:Entry time of Hfr chromosome into recipient cell. Time a d e f h 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 + + + + + + + + + + + + + + + + + + + + + + + + + + + + + + + + +arrow_forward
- An Hfr strain that is leuA+ and thiL+ was mixed with a strain thatis leuA− and thiL−. In the data points shown in the following graph,the conjugation was interrupted at different time points, and thepercentage of recombinants for each gene was determined bystreaking on a medium that lacked either leucine or thiamine.Make a calculation.arrow_forwardTwo auxotrophic triple Escherichia coli strains (A: met- phe- ade- val+ bio+ thr+ and B: met+ phe+ ade+ val- bio- thr-) are mixed in LB liquid medium, diluted and then spread on LB solid rich medium. Six colonies are observed: Then, replicates are performed on 6 different media (minimum medium + glucose + indicated substances). The results are shown below. Determine the genotype of the 6 colonies observed. Which ones are from strain A? From strain B? Which hypotheses can explain these results and which one do you prefer? met phe val bio Abbreviations: met ade val thr phe ade bio thr Met: methionine; Phe: phenylalanine; Ade: adenine; Val: valine; Bio: biotin; Thr: threonine.arrow_forwardConjugation between an F+ and an F- cell will produce: 2 F+ cells and 2 F- cells O 2 F+ cells 4 F+ offspring 1 F+ cell and 1 F- cellarrow_forward
- The figure below shows a partial chromosome map of an E. coli Hfr strain. Each mark = 10 minutes between conjugation transfer time. If transfer of genes begins at “*” relative to the origin of transfer, what is one of the predicted results from this map? It would take less than 30 minutes to transfer all of the genes that are shown. gal and azi will rarely be transferred together. gal and ton will rarely be transferred together. Ten minutes after transfer of ton, lac will be transferred. This strain will produce very few gal recombinants.arrow_forwardDNA from a strain of Bacillus subtilis with genotype a+ b+ c+ d+ e+ is used to transform a strain with genotype a− b− c− d− e−. Pairs of genes are checked for cotransformation, and the following results are obtained: Pair of genes Cotransformation Pair of genes Cotransformation a+ and b+ No b+ and d+ No a+ and c+ No b+ and e+ Yes a+ and d+ Yes c+ and d+ No a+ and e+ Yes c+ and e+ Yes b+ and c+ Yes d+ and e+ No On the basis of these results, what is the order of the genes on the bacterial chromosome?arrow_forwardWhat is the result of conjugation between F and F cells?arrow_forward
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genetic recombination strategies of bacteria CONJUGATION, TRANSDUCTION AND TRANSFORMATION; Author: Scientist Cindy;https://www.youtube.com/watch?v=_Va8FZJEl9A;License: Standard youtube license