Mathematical Statistics with Applications
7th Edition
ISBN: 9780495110811
Author: Dennis Wackerly, William Mendenhall, Richard L. Scheaffer
Publisher: Cengage Learning
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Chapter 13, Problem 94SE
a.
To determine
Justify that
b.
To determine
Show that
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A snack food manufacturer estimates that the variance of the number of grams of carbohydrates in servings of its tortilla chips is
1.34.
A dietician is asked to test this claim and finds that a random sample of
16
servings has a variance of
1.22.
At
α=0.05,
is there enough evidence to reject the manufacturer's claim? Assume the population is normally distributed. Complete parts (a) through (e) below.
2.Test the hypothesis that the average content of containers of a particular lubricant is 10 liters if the contents of a random sample of 10 containers are 10.1, 9.9, 10.2, 10.3, 10.3, 9.7, 9.8, 10.5, 10.2, and 9.8 liters. Use alpha 0.01 and assume that the distribution of content is normal.
A snack food manufacturer estimates that the variance of the number of grams of carbohydrates in servings of its tortilla chips is
1.33.
A dietician is asked to test this claim and finds that a random sample of
24
servings has a variance of
1.37.
At
α=0.01,
is there enough evidence to reject the manufacturer's claim? Assume the population is normally distributed. Complete parts (a) through (e) below.
(a) Write the claim mathematically and identify
H0
and
Ha.
A.
H0:
σ2≤1.33
(Claim)
Ha:
σ2>1.33
B.
H0:
σ2≠1.33
Ha:
σ2=1.33
(Claim)
C.
H0:
σ2≥1.33
Ha:
σ2<1.33
(Claim)
D.
H0:
σ2=1.33
(Claim)
Ha:
σ2≠1.33
(b) Find the critical value(s) and identify the rejection region(s).
The critical value(s) is(are)
enter your response here.
(Round to two decimal places as needed. Use a comma to separate answers as needed.)
Choose the correct statement below and fill in the corresponding answer boxes.
A.
The…
Chapter 13 Solutions
Mathematical Statistics with Applications
Ch. 13.2 - The reaction times for two different stimuli in a...Ch. 13.2 - Prob. 2ECh. 13.4 - State the assumptions underlying the ANOVA of a...Ch. 13.4 - Prob. 4ECh. 13.4 - Prob. 5ECh. 13.4 - Suppose that independent samples of sizes n1, n2,,...Ch. 13.4 - Four chemical plants, producing the same products...Ch. 13.4 - Prob. 8ECh. 13.4 - Prob. 9ECh. 13.4 - A clinical psychologist wished to compare three...
Ch. 13.4 - It is believed that women in the postmenopausal...Ch. 13.4 - If vegetables intended for human consumption...Ch. 13.4 - One portion of the research described in a paper...Ch. 13.4 - The Florida Game and Fish Commission desires to...Ch. 13.4 - Prob. 15ECh. 13.4 - An experiment was conducted to examine the effect...Ch. 13.5 - Prob. 17ECh. 13.5 - Refer to Exercise 13.17 and consider YiYi for i ...Ch. 13.5 - Refer to the statistical model for the one-way...Ch. 13.7 - Refer to Examples 13.2 and 13.3. a Use the portion...Ch. 13.7 - Refer to Examples 13.2 and 13.4. a Use the portion...Ch. 13.7 - a Based on your answers to Exercises 13.20 and...Ch. 13.7 - Refer to Exercise 13.7. a Construct a 95%...Ch. 13.7 - Prob. 24ECh. 13.7 - Prob. 25ECh. 13.7 - Prob. 26ECh. 13.7 - Prob. 27ECh. 13.7 - Prob. 28ECh. 13.7 - Prob. 29ECh. 13.7 - Prob. 30ECh. 13.7 - Prob. 31ECh. 13.7 - Prob. 32ECh. 13.7 - Prob. 33ECh. 13.7 - Prob. 34ECh. 13.7 - Prob. 35ECh. 13.8 - Prob. 36ECh. 13.8 - Prob. 37ECh. 13.8 - Prob. 38ECh. 13.8 - Prob. 39ECh. 13.8 - Prob. 40ECh. 13.9 - Prob. 41ECh. 13.9 - The accompanying table presents data on yields...Ch. 13.9 - Refer to Exercise 13.42. Why was a randomized...Ch. 13.9 - Prob. 44ECh. 13.9 - Prob. 45ECh. 13.9 - Prob. 46ECh. 13.9 - Prob. 47ECh. 13.9 - Prob. 48ECh. 13.9 - Prob. 49ECh. 13.9 - Prob. 50ECh. 13.9 - Prob. 51ECh. 13.10 - Prob. 52ECh. 13.10 - Prob. 53ECh. 13.10 - Prob. 54ECh. 13.10 - Refer to Exercise 13.46. Construct a 95%...Ch. 13.10 - Prob. 56ECh. 13.10 - Prob. 57ECh. 13.11 - Prob. 58ECh. 13.11 - Prob. 59ECh. 13.11 - Prob. 60ECh. 13.11 - Prob. 61ECh. 13.11 - Prob. 62ECh. 13.12 - Prob. 63ECh. 13.12 - Prob. 64ECh. 13.12 - Prob. 65ECh. 13.12 - Prob. 66ECh. 13.12 - Prob. 67ECh. 13.12 - Prob. 68ECh. 13.13 - Prob. 69ECh. 13.13 - Prob. 70ECh. 13.13 - Refer to Exercise 13.42. Answer part (a) by...Ch. 13.13 - Refer to Exercise 13.45. Answer part (b) by...Ch. 13 - Prob. 73SECh. 13 - Prob. 74SECh. 13 - Prob. 75SECh. 13 - Prob. 77SECh. 13 - A study was initiated to investigate the effect of...Ch. 13 - Prob. 79SECh. 13 - A dealer has in stock three cars (models A, B, and...Ch. 13 - In the hope of attracting more riders, a city...Ch. 13 - Prob. 84SECh. 13 - Prob. 85SECh. 13 - Prob. 86SECh. 13 - Prob. 87SECh. 13 - Prob. 88SECh. 13 - Prob. 89SECh. 13 - Prob. 90SECh. 13 - Prob. 92SECh. 13 - Prob. 94SE
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.Similar questions
- Consider the following measurements of blood hemoglobin concentrations (in g/dL) from three human populations at different geographic locations: population1 = [ 14.7 , 15.22, 15.28, 16.58, 15.10 ] population2 = [ 15.66, 15.91, 14.41, 14.73, 15.09] population3 = [ 17.12, 16.42, 16.43, 17.33] What is the standard error of the difference between the means of population 1 and population 2, needed to calculate the Tukey-Kramer q-statistic? What is the Tukey-Kramer q-statistic for populations 1 and 2? (Report the absolute value, if you get a negative number, multiply by -1)arrow_forwardBased on the JMP Output below, can you assume the population variances are equal? JMP Output Test F Ratio DFNum DFDen Prob > F O'Brien[.5] 0.5289 2 57 0.5921 Brown-Forsythe 0.4225 2 57 0.6575 Levene 0.6231 2 57 0.5399 Bartlett 0.4893 2 . 0.6131 Group of answer choices Yes, since the Brown-Forsythe p-value = 0.6575 > 0.10 Yes, since the Brown-Forsythe p-value = 0.6575 > 0.05 Yes, since the Brown-Forsythe p-value = 0.4225 > 0.10. Yes, since the Brown-Forsythe p-value = 0.4225 > 0.05 No, since the Brown-Forsythe p-value = 0.6575 > 0.10 No, since the Brown-Forsythe p-value = 0.6575 > 0.05 No, since the Brown-Forsythe p-value = 0.4225 > 0.10 No, since the Brown-Forsythe p-value = 0.4225 > 0.05arrow_forwardLet X1,...,Xn be an iid sample from f(x | θ) = θ xθ−1, 0 < x < 1, where the parameter θ is positive. Find the MLE and MOM estimators for θarrow_forward
- Let X1,...,Xn be an iid sample from f(x | θ) = θxθ−1, 0 < x < 1, where the parameter θ is positive. Find the MLE and MOM estimators for θarrow_forwardA snack food manufacturer estimates that the variance of the number of grams of carbohydrates in servings of its tortilla chips is 1.141.14. A dietician is asked to test this claim and finds that a random sample of 2424 servings has a variance of 0.950.95. At alpha equals 0.10α=0.10, is there enough evidence to reject the manufacturer's claim? Assume the population is normally distributed.arrow_forwardConsider the following hypothesis statement using α=0.01 and data from two independent samples. Assume the population variances are equal and the populations are normally distributed. Complete parts a and b. H0: μ1−μ2=0 x1=14.5 x2=13.0 H1: μ1−μ2≠0 s1=2.6 s2=3.3 n1=22 n2=15 a. Calculate the appropriate test statistic and interpret the result. The test statistic is? The critical value(s) is(are)? b. Identify the p-value from part a and interpret the result.arrow_forward
- A researcher is testing a null hypothesis that states, H0: μ= 50. A sample of 25 scores is selected and M= 55. Assuming the sample variance is s2 = 100, compute the estimated standard error and the t-statistic. Is this sample sufficient to reject the null hypothesis using a two-tailed test with a= .05? Note: This is a two-tailed test HA: df= tα or t value for the critical region = sM = t = Decisionarrow_forwardThe following data were obtained from a two-factor independent-measures experiment with n=10 participants in each treatment condition. B1 B2 A1 M=4 T=50 SS=20 M=7 T=20 SS=28 A2 M=1 T=20 SS=12 M=4 T=30 SS-20 a. Calculate degrees of freedom and locate the critical region for each of the three tests (a=.05) b. Calculate the three F-ratios c. State the conclusion for each test.arrow_forward
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