EBK LIFE: THE SCIENCE OF BIOLOGY
11th Edition
ISBN: 8220103935432
Author: Sadava
Publisher: MAC HIGHER
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Chapter 13.1, Problem 4R
Summary Introduction
To review:
The experiments utilizing radioactive isotopes that would prove deoxyribonucleic acid (DNA) to be the genetic material and not proteins that are transferred to bacterial cells.
Introduction:
Some bacteria reproduce by various methods, one of them is by conjugation. During this type of reproduction, one of the bacteria carry an ‘F’ factor (genetic material called the plasmid), which is a determinant of donor cell, while the other bacteria does not carry any factor, this being the determinant of a recipient cell. The donor cell or the F+ bacteria, forms a conjugation tube between itself and the recipient cell (F−) in order to transfer the F-plasmid.
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Consider the following experiment. First, large populations of two mutant strains of Escherichia coli are mixed, each requiring a different, single amino acid. After plating them onto a minimal medium, 45 colonies grew. Which of the following may explain this result?
A) The colonies may be due to back mutation (reversion).
B) The colonies may be due to recombination.
C) Either A or B is possible.
D) Neither A nor B is possible.
In Hershey-Chase experiment, bacteriophages protein coats were tagged with radioactive isotope S-32. These phages were used to infect E. coli cells and the cells were further centrifuged to form pellets.
Why was the radioactivity level of S-32 found greater outside the cells compared to the E. coli cell pellets? Explain briefly.
If the experiment is repeated in the same manner but this time the phage protein coats are labelled with isotope X and the phage DNA with isotope Y, which isotope’s radioactivity will be found in greater amounts in the E. coli cell pellets after centrifugation? Explain briefly.
We have two specific strains of E. coli that have shown horizontal gene transfer (HGT) when mixed. To experimentally determine the method of HGT that is happening, the following conditions are set up in different tubes of culture media:
A) Donor and recipient strain mixed together (control - no treatment).
B) Donor and recipient strains mixed together, DNase added (can digest DNA in solution, not within cells).C) Special tube containing a membrane filter (with pores that allow DNA and viruses to pass through, but not bacterial cells) that separates two compartments. Donor strain is added on one side, the recipient strain on the other (they are separated by the filter).D) Donor and recipient strains mixed together, with chemical that inactivates viruses (chemical affects bacteriophages in solution so they are unable to attach to cells).
The results:
Tubes A, B, and D: HGT was observed.
Tube C: HGT was NOT observed.
Based on this, which type of HGT was occurring?
Conjugation,…
Chapter 13 Solutions
EBK LIFE: THE SCIENCE OF BIOLOGY
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
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- Based on the following wild type DNA sequence, indicate if each of the mutations should be classified as : insertion, deletion, missense, nonsense, silent (Use the provided Genetic Code table and remember you have been given DNA sequence). Wild Type: 5’ ATG GCT AGA GTC GAG TTG 3’ Mutant 1: 5’ ATG GCA GAG TCG AGT TG 3’ Mutant 2: 5’ ATG GCT TGA GTC GAG TTG 3’ Mutant 3: 5’ ATG GCT AGA GTT GAG TTG 3’ Mutant 4: 5’ ATG GCT AGA AGT CGA GTT G 3’ Mutant 5: 5’ ATG GCT AGA ATC GAG GTT 3’arrow_forwardXeroderma pigmentosum is a genetic disease caused by an error in the nucleotide excision repair process that fixes damage to DNA by ultraviolet light. Studies have shown that it can result from mutations in any one of seven genes. What can you infer from this finding? A) There are seven genes that produce the same protein B) These seven genes are the most easily damaged by ultraviolet light. C) There are seven enzymes involved in the nucleotide excision repair process. D) These mutations have resulted from translocation of gene segments.arrow_forwardIn the Hershey–Chase experiment, the radioactive label 32P was present inside bacterial cells (i.e., in the pellet), whereas the radioactive label 35S waspresent outside bacterial cells (in the supernatant). What would the researchers have concluded had the reverse been true, that is, if the radioactive label 35S were inside the cells and the radioactive label 32P were outside the cells?arrow_forward
- For each of the following ( A & B ) provide the method of transfer and a brief explanation as to why the method would not take place under the conditions described . 1. Which method of DNA transfer between bacteria would not take place if the donor and recipient were separated by a filter with a pore size of 0.45 um or another physical barrier 2. Which method of transfer would be blocked by the presence of high concentrations of DNAase ( enzymes capable of degrading DNA ) ?arrow_forwardGive Detailed explanation Solution (no need Handwritten)arrow_forwardBy conducting conjugation experiments between Hfr and recipientstrains, Wollman and Jacob mapped the order of many bacterialgenes. Throughout the course of their studies, they identified severaldifferent Hfr strains in which the F-factor DNA had been integratedat different places along the bacterial chromosome. A sample of theirexperimental results is shown in the following table:What information do you know based on the question and your understanding of the topic?arrow_forward
- Jackson Wang is a biologist working with the genetics of a thermophilic bacterium. He cloned a heat shock gene from the bacteria for further analysis. After cloning, he isolated the plasmid carrying his gene of interest for sequencing. Jackson finally received the nucleotide sequence of his gene. Explain in detail how he could verify whether the nucleotide sequence matches his gene of interest using the bioinformatics databases available.arrow_forwardBacterial conjugation has medical consequences. For example, certain plasmids contain genes that code for toxins. The causative agent of a deadly form of food poisoning, E. coli 0157, synthesizes a toxin that causes massive bloody diarrhea and kidney failure. This toxin is now believed to have originated in Shigella, another bacterium that causes dysentery. Similarly, the growing problem of antibiotic resistance is partly attributable to the spread of antibioticresistant genes among bacterial populations. Antibiotic resistance develops because antibiotics are overused in medical practice and in livestock feeds. Suggest a mechanism by which this extensive use promotes antibiotic resistance.arrow_forwardGeneral recombination occurs in bacteria where it is involved in several types of intermicrobial DNA transfer. What are these types of transfer, and by what mechanisms do they occur?arrow_forward
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