Mathematical Statistics with Applications
7th Edition
ISBN: 9780495110811
Author: Dennis Wackerly, William Mendenhall, Richard L. Scheaffer
Publisher: Cengage Learning
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Chapter 13.12, Problem 63E
To determine
Explain the reason for difference in length of the confidence interval.
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The director of the rabies control section in a city health department wishes to draw a sample from the department's records of dog bites reported during the past year in order to estimate the mean age of persons bitten. He wants a 95 percent confidence interval, he will be satisfied to let E = 2.5, and from previous studies he estimates the population standard deviation to be about 15 years. How large a sample should be drawn?
(a)A random sample of 25 college males was obtained and each was asked to report their actual height and what they wished as their ideal height. A 95% confidence interval for µd = average difference between their ideal and actual heights was 0.8" to 2.2". Based on this interval, which one of the null hypotheses below (versus a two-sided alternative) can be rejected?
all the above
c. H0: µd = 1.5
H0: µd = 0.5
b. H0: µd = 1.0
H0: µd = 2.0
(b)Which of the following is a correct form of an alternate hypothesis for paired data?
H1: μd = p
H1: μ1 ≠ μ2
H1: μd > 0
H1: μ1 = μ2
(C)Which of the following is always the null hypothesis for two sample proportions?
d. H0: p1 = 3
H0: p1 < μ2
H0: p1 ≠ p2
H0: p1 = p2
a simple random sample of women aged 18-24 is selected, and the systolic blood pressure of each woman is measured. The results (in mmHg) are as follows: x=122.1, s=14.4. The sample size is less than 20. A 99% confidence interval for the population mean is found to be
Chapter 13 Solutions
Mathematical Statistics with Applications
Ch. 13.2 - The reaction times for two different stimuli in a...Ch. 13.2 - Prob. 2ECh. 13.4 - State the assumptions underlying the ANOVA of a...Ch. 13.4 - Prob. 4ECh. 13.4 - Prob. 5ECh. 13.4 - Suppose that independent samples of sizes n1, n2,,...Ch. 13.4 - Four chemical plants, producing the same products...Ch. 13.4 - Prob. 8ECh. 13.4 - Prob. 9ECh. 13.4 - A clinical psychologist wished to compare three...
Ch. 13.4 - It is believed that women in the postmenopausal...Ch. 13.4 - If vegetables intended for human consumption...Ch. 13.4 - One portion of the research described in a paper...Ch. 13.4 - The Florida Game and Fish Commission desires to...Ch. 13.4 - Prob. 15ECh. 13.4 - An experiment was conducted to examine the effect...Ch. 13.5 - Prob. 17ECh. 13.5 - Refer to Exercise 13.17 and consider YiYi for i ...Ch. 13.5 - Refer to the statistical model for the one-way...Ch. 13.7 - Refer to Examples 13.2 and 13.3. a Use the portion...Ch. 13.7 - Refer to Examples 13.2 and 13.4. a Use the portion...Ch. 13.7 - a Based on your answers to Exercises 13.20 and...Ch. 13.7 - Refer to Exercise 13.7. a Construct a 95%...Ch. 13.7 - Prob. 24ECh. 13.7 - Prob. 25ECh. 13.7 - Prob. 26ECh. 13.7 - Prob. 27ECh. 13.7 - Prob. 28ECh. 13.7 - Prob. 29ECh. 13.7 - Prob. 30ECh. 13.7 - Prob. 31ECh. 13.7 - Prob. 32ECh. 13.7 - Prob. 33ECh. 13.7 - Prob. 34ECh. 13.7 - Prob. 35ECh. 13.8 - Prob. 36ECh. 13.8 - Prob. 37ECh. 13.8 - Prob. 38ECh. 13.8 - Prob. 39ECh. 13.8 - Prob. 40ECh. 13.9 - Prob. 41ECh. 13.9 - The accompanying table presents data on yields...Ch. 13.9 - Refer to Exercise 13.42. Why was a randomized...Ch. 13.9 - Prob. 44ECh. 13.9 - Prob. 45ECh. 13.9 - Prob. 46ECh. 13.9 - Prob. 47ECh. 13.9 - Prob. 48ECh. 13.9 - Prob. 49ECh. 13.9 - Prob. 50ECh. 13.9 - Prob. 51ECh. 13.10 - Prob. 52ECh. 13.10 - Prob. 53ECh. 13.10 - Prob. 54ECh. 13.10 - Refer to Exercise 13.46. Construct a 95%...Ch. 13.10 - Prob. 56ECh. 13.10 - Prob. 57ECh. 13.11 - Prob. 58ECh. 13.11 - Prob. 59ECh. 13.11 - Prob. 60ECh. 13.11 - Prob. 61ECh. 13.11 - Prob. 62ECh. 13.12 - Prob. 63ECh. 13.12 - Prob. 64ECh. 13.12 - Prob. 65ECh. 13.12 - Prob. 66ECh. 13.12 - Prob. 67ECh. 13.12 - Prob. 68ECh. 13.13 - Prob. 69ECh. 13.13 - Prob. 70ECh. 13.13 - Refer to Exercise 13.42. Answer part (a) by...Ch. 13.13 - Refer to Exercise 13.45. Answer part (b) by...Ch. 13 - Prob. 73SECh. 13 - Prob. 74SECh. 13 - Prob. 75SECh. 13 - Prob. 77SECh. 13 - A study was initiated to investigate the effect of...Ch. 13 - Prob. 79SECh. 13 - A dealer has in stock three cars (models A, B, and...Ch. 13 - In the hope of attracting more riders, a city...Ch. 13 - Prob. 84SECh. 13 - Prob. 85SECh. 13 - Prob. 86SECh. 13 - Prob. 87SECh. 13 - Prob. 88SECh. 13 - Prob. 89SECh. 13 - Prob. 90SECh. 13 - Prob. 92SECh. 13 - Prob. 94SE
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- Here are summary statistics for randomly selected weights of newborn girls: n=218, x=32.8hg,s=6.2hg. Construct a confidence interval estimate of the mean. Use a 90% confidence level. Are these results very different from the confidence interval 32.0hg <μ<33.4 hg with only 20 sample values, x=32.7hg, and s=1.8hg? What is the confidence interval for the population mean μ?_____hg <μ<___hg Are the results between the two confidence intervals very different?arrow_forwardBased on your confidence interval from the previous problem, can you conclude that the mean permeability coefficient at 60∘60∘C differs from that at 61∘61∘C at the 0.05 level of significance? A. Yes, because the 95% confidence interval includes 0 B. No, because the 95% confidence interval includes 0 C. Yes, because the 95% confidence interval does not include 0 D. No, because the 95% confidence interval does not include 0 E. It is impossible answer this question only using the 95% confidence interval.arrow_forwardA 30 month study is conducted to determine the difference in rates of accidents per month between two departments in an assembly plant. If a sample of 12 from the first department averaged 12.3 accidents per month with a standard deviation of 3.5, and a sample of 9 from the second department averaged 7.6 accidents per month with standard deviation of 3.4, find: The t-value for a 95% confidence interval is: A. 2.09302 B. 1.724718 C. 2.08596 D. 1.729133 E. none of the precedingarrow_forward
- A random sample of nn measurements was selected from a population with standard deviation σ=11.4 and unknown mean μ. Calculate a 95% confidence interval for μ for each of the following situations: (a) n=40, x¯=74 ≤μ≤ (b) n=55, x¯=74 ≤μ≤ (c) n=70, x¯=74 ≤μ≤arrow_forwardHere are summary statistics for randomly selected weights of newborn girls: n=191, x=28.9 hg, s =7.8hg. Construct a confidence interval estimate of the mean. Use a 90% confidence level. Are these results very different from the confidence interval 27.1 hg<u<30.5 hg with only 13 sample values, x=28.8 hg, and s=3.5 hg? What is the confidence interval for the population mean u? Are the results between the two confidence intervals very different?arrow_forwardA regression analysis yields the following information: Y^=2.21+1.49X ; n = 10; sy∙x = 1.66; ΣX = 32; ΣX2 = 134; ∑(X−X¯¯¯¯)2=31.6 Compute the 95% confidence interval when X = 4.arrow_forward
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