Biological Science (6th Edition)
6th Edition
ISBN: 9780321976499
Author: Scott Freeman, Kim Quillin, Lizabeth Allison, Michael Black, Emily Taylor, Greg Podgorski, Jeff Carmichael
Publisher: PEARSON
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Chapter 14, Problem 25PIAT
Summary Introduction
To review:
The reason behind the occurrence of color blindness in the son without Adrenoleukodystrophy (ALD).
Introduction:
Adrenoleukodystrophy (ALD) is a type of X-linked disorder. It occurs as a result of mutation in the ABCD1 gene, which is present on the Xq28 chromosome. Furthermore, the nonfunctioning of these enzymes damages the myelin sheath present on the axon, which further causes degeneration of neuron.
A woman is heterozygous for a colorblindness allele. At a site on the chromosome with the color blindness allele, a new mutation occurs causing ALD, creating one chromosome with an allele for color blindness and an allele for ALD. Woman bears a colorblind child but does not have ALD.
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Chapter 14 Solutions
Biological Science (6th Edition)
Ch. 14 - 1. The genes for the trails that Mendel worked...Ch. 14 - 2. CAUTION Why is the pea wrinkled-seed allele a...Ch. 14 - Prob. 3TYKCh. 14 - 4. Mendel’s rules do not correctly predict...Ch. 14 - Prob. 5TYKCh. 14 - Prob. 6TYKCh. 14 - Example Problem Two black female mice are crossed...Ch. 14 - Prob. 8TYKCh. 14 - Prob. 9TYPSSCh. 14 - Prob. 10TYPSS
Ch. 14 - 11. In garden peas, yellow seeds (Y) are dominant...Ch. 14 - Prob. 12TYPSSCh. 14 - The smooth feathers on the back of the neck in...Ch. 14 - SOCIETY As a genetic counselor, you advise couples...Ch. 14 - 15. Suppose you are heterozygous for two genes...Ch. 14 - Suppose a woman with blood type O married a man...Ch. 14 - Prob. 17TYPSSCh. 14 - Society Two mothers give birth to sons at the same...Ch. 14 - Prob. 19TYPSSCh. 14 - QUANTITATIVE Recall that hemophilia is an X-linked...Ch. 14 - Prob. 21PIATCh. 14 - Given the pedigree, what is the most likely mode...Ch. 14 - Prob. 23PIATCh. 14 - QUANTITATIVE If the son with ALD in the third...Ch. 14 - Prob. 25PIATCh. 14 - Prob. 26PIAT
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- In a particular country in sub-Saharan Africa, a medical study revealed that 0.075% of the country's population are suffering from sickle-cell anemia. Sickle cell disease is caused by a mutation in the haemoglobin-Beta gene found on chromosome 11. Sickle cell anemia is controlled by a pair of alleles, H and h, where the individuals with the illness have the homozygous recessive genotype; those with normal red blood cells have the alternative genotype. Using the Hardy-Weinberg's equation, calculate the percentage of the population of the two genotypes for normal blood cells. In a few remote areas in that country, the percentage of sickle cell anemia reaches as high as 5%. Calculate the percentage of homozygous and heterozygous individuals with the normal blood cells and find the ratio for both phenotypes.arrow_forwardConsider a couple: a woman who is homozygous for a recessive mutation that causes X-linked colorblindness, and a man with full color vision (he does not carry a copy of the mutation). a) What is the probability that a son of this couple will be colorblind? b) What is the probability that a daughter of the couple will be colorblind?arrow_forwardIn flies, small wings are recessive to normal wings. If a cross between two flies produces 8 small-wing offspring and 28 normal-wing offspring, what are the most likely genotypes of the parents? (Use SS to represent the normal-wing allele and ss to represent the short-wing allele.)arrow_forward
- The pedigree below shows a family affected by a disease. Assume that the individuals marked with an asterisk (*) do not carry any allele associated with the affected phenotype, no other mutation spontaneously occurred, and complete penetrance. Answer the following questions below. Use the notation XR for the allele associated with the dominant phenotype and Xr for the allele associated with the recessive phenotype. Q1) Give the genotypes for as many individuals in the pedigree as possible.arrow_forwardRed-green color blindness is caused by a mutation in the gene coding for one the Ospin proteins which are needed for color Vision the diagram in the image shows the inheritance of red-green color blindness in one family. person 12 is pregnant with her forth child, what is the probability that this child will be a male with red-green color blindness explain the answer by drawing a genetic diagram using the following symbols in the second image.arrow_forwardA phenotypically normal boy has 45 chromosomes, but his sister, who has Down syndrome, has 46. Suggest an explanation that explains both children.arrow_forward
- My friend Pierre is red-green color blind and so is his father, but his mother is not color-blind. In the diagram below: a) Indicate the sex chromosomes of each member of Pierre's family b) Indicate the color-blindness allele associated with each chromosome of Pierre and his family (let B represent the color vision allele and let b represent a color blindness allele. If an allele cannot be determined with certainty, label the chromosome with a question mark c) Finally, determine the probability that Pierre's sister is color blind. Explain your reasoning.arrow_forwardUsing a particular family as a model, how do you distinguish nuclear from extrachromosomal inheritance? Give a specific example.arrow_forwardFragile X is a disorder which causes mental impairment in affected individuals. The trait which is due to a mutation in the FMR1 gene on the X chromosome is inherited in a recessive manner. An unaffected son was born to an affected man and an unaffected woman. The woman’s mother was affected while the father was normal. a. Indicate the gene notation. b. Give the genotype of the son. c. Is it possible for the couple to have an affected daughter? affected son? Derive the genotypic and phenotypic ratios for the offspring. Show and label your solutions properly. d. If the couple has four children, what is the probability that they will have three normal daughters and one normal son?arrow_forward
- In the fruit fly, recessive mutations in either of two independently assorting genes, brown and purple, prevent the synthesis of red pigment in the eyes. Thus, homozygotes for either of these mutations have brownish-purple eyes. However, heterozygotes for both of these mutations have dark red, that is, wild-type eyes. If such double heterozygotes are intercrossed, what kinds of progeny will be produced, and in what proportions?arrow_forwardEye colors are passed down through generations, but sometimes genetic variations can lead to surprising results in eye colors (dark eye color, still rocks!?) Some examples are found below. Is there truth behind the following? Provide explanations for your answer. Two parents with blue eyes cannot have a brown-eyed child and vice-versa. Eyes with more than one color stems from parents with two different eye colors. People with violet eyes are mutants. People with red or pinkish eye color can have dark-eyed parents.arrow_forwardFor a certain gene in a diploid organism, eight units ofprotein product are needed for normal function. Eachwild-type allele produces five units.a. If a mutation creates a null allele, do you think thisallele will be recessive or dominant?b. What assumptions need to be made to answer part a?arrow_forward
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