   # Consider the titration of 100.0 mL of 0.100 M H 2 NNH 2 ( K b = 3.0 × 10 −6 ) by 0.200 M HNO 3 . Calculate the pH of the resulting solution after the following volumes of HNO 3 have been added. a. 0.0 mL b. 20.0 mL c. 25.0 mL d. 40.0 mL e. 50.0 mL f. 100.0 mL ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 14, Problem 60E
Textbook Problem
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## Consider the titration of 100.0 mL of 0.100 M H2NNH2 (Kb = 3.0 × 10−6) by 0.200 M HNO3. Calculate the pH of the resulting solution after the following volumes of HNO3 have been added.a. 0.0 mLb. 20.0 mLc. 25.0 mLd. 40.0 mLe. 50.0 mLf. 100.0 mL

(a)

Interpretation Introduction

Interpretation: The titration of H2NNH2 with different volumes of HNO3 is given. The pH of each solution is to be calculated.

Concept introduction: Titration is a quantitative chemical analysis method that is used for the determination of concentration of an unknown solution. In acid base titration, the neutralization of either acid or base is done with a base or acid respectively of known concentration. This helps to determine the unknown concentration of acid or base.

When the amount of the titrant added is just sufficient for the neutralization of analyte is called equivalence point. At this point equal equivalents of both the acid and base are added.

To determine: The value of pH of solution when 0.0mL HNO3 has been added to it.

### Explanation of Solution

Explanation

The value of pH of solution when 0.0mL HNO3 has been added is. 10.74_ .

Given:

The concentration of H2NNH2 is 0.100M

The concentration of HNO3 is 0.200M .

The volume of H2NNH2 is 100.0mL .

The volume of HNO3 is 0.0mL .

The value of Kb of H2NNH2 is 3.0×106 .

The conversion of mL into L is done as,

1mL=0.001L

Hence the conversion of 100mL into L is done as,

100mL=100×0.001L=0.100L

The reaction is represented as,

H2NNH2+H2OH2NNH3++OH

Make the ICE table for the reaction between H2NNH2 and H2O .

H2NNH2+H2OH2NNH3++OHInitial moles:0.10000Change:x+xxFinalmoles:0.100xxx

The equilibrium ratio for the given reaction is,

Kb=[H2NNH3+][OH][H2NNH2]

Substitute the calculated concentration values in the above expression

(b)

Interpretation Introduction

Interpretation: The titration of H2NNH2 with different volumes of HNO3 is given. The pH of each solution is to be calculated.

Concept introduction: Titration is a quantitative chemical analysis method that is used for the determination of concentration of an unknown solution. In acid base titration, the neutralization of either acid or base is done with a base or acid respectively of known concentration. This helps to determine the unknown concentration of acid or base.

When the amount of the titrant added is just sufficient for the neutralization of analyte is called equivalence point. At this point equal equivalents of both the acid and base are added.

To determine: The value of pH of solution when 20.0mL HNO3 has been added to it.

(c)

Interpretation Introduction

Interpretation: The titration of H2NNH2 with different volumes of HNO3 is given. The pH of each solution is to be calculated.

Concept introduction: Titration is a quantitative chemical analysis method that is used for the determination of concentration of an unknown solution. In acid base titration, the neutralization of either acid or base is done with a base or acid respectively of known concentration. This helps to determine the unknown concentration of acid or base.

When the amount of the titrant added is just sufficient for the neutralization of analyte is called equivalence point. At this point equal equivalents of both the acid and base are added.

To determine: The value of pH of solution when 25.0mL HNO3 has been added to it.

(d)

Interpretation Introduction

Interpretation: The titration of H2NNH2 with different volumes of HNO3 is given. The pH of each solution is to be calculated.

Concept introduction: Titration is a quantitative chemical analysis method that is used for the determination of concentration of an unknown solution. In acid base titration, the neutralization of either acid or base is done with a base or acid respectively of known concentration. This helps to determine the unknown concentration of acid or base.

When the amount of the titrant added is just sufficient for the neutralization of analyte is called equivalence point. At this point equal equivalents of both the acid and base are added.

To determine: The value of pH of solution when 40.0mL HNO3 has been added to it.

(e)

Interpretation Introduction

Interpretation: The titration of H2NNH2 with different volumes of HNO3 is given. The pH of each solution is to be calculated.

Concept introduction: Titration is a quantitative chemical analysis method that is used for the determination of concentration of an unknown solution. In acid base titration, the neutralization of either acid or base is done with a base or acid respectively of known concentration. This helps to determine the unknown concentration of acid or base.

When the amount of the titrant added is just sufficient for the neutralization of analyte is called equivalence point. At this point equal equivalents of both the acid and base are added.

To determine: The value of pH of solution when 50.0mL HNO3 has been added to it.

(f)

Interpretation Introduction

Interpretation: The titration of H2NNH2 with different volumes of HNO3 is given. The pH of each solution is to be calculated.

Concept introduction: Titration is a quantitative chemical analysis method that is used for the determination of concentration of an unknown solution. In acid base titration, the neutralization of either acid or base is done with a base or acid respectively of known concentration. This helps to determine the unknown concentration of acid or base.

When the amount of the titrant added is just sufficient for the neutralization of analyte is called equivalence point. At this point equal equivalents of both the acid and base are added.

To determine: The value of pH of solution when 100.0mL HNO3 has been added to it.

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