Glencoe Physics: Principles and Problems, Student Edition
Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN: 9780078807213
Author: Paul W. Zitzewitz
Publisher: Glencoe/McGraw-Hill
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Chapter 14, Problem 94A

(a)

To determine

The time taken by P to complete one full swing using a 10m long rope.

(a)

Expert Solution
Check Mark

Answer to Problem 94A

Time is 6.34s .

Explanation of Solution

Given:

The length of the rope, l=10 m ,

Formula used:

  T=2πlg    .......(1)

Here, T is the time period of the pendulum, l is the length of the pendulum and g is the acceleration due to gravity.

Calculation:

Substituting 10 m in l and 9.8 m/s2 in g in equation (1),

  T=2π109.8T=6.34 s

Conclusion:

Hence, the time is 6.34s .

(b)

To determine

The difference of period of P and Mike.

(b)

Expert Solution
Check Mark

Explanation of Solution

Given:

The length of the rope, l=10 m .

It is assumed that, the weight of P be x , then weight of Mike is x+20 .

Formula used:

  T=2πlg    .......(1)

Here, T is the time period of the pendulum, l is the length of the pendulum and g is the acceleration due to gravity.

Calculation:

(b) There is no difference in time period of Mike and P as the mass persons would not effect the time period.

Conclusion:

Hence, no difference is found.

(c)

To determine

The point at which the KE is maximum.

(c)

Expert Solution
Check Mark

Explanation of Solution

Given:

The length of the rope, l=10 m .

Formula used:

  T=2πlg    .......(1)

Here, T is the time period of the pendulum, l is the length of the pendulum and g is the acceleration due to gravity.

Calculation:

The KE or kinetic energy is maximum at the bottom of the swing.

Conclusion:

Hence, KE will take maximum value.

(d)

To determine

The point at which the potential difference is maximum.

(d)

Expert Solution
Check Mark

Explanation of Solution

Given:

The length of the rope, l=10 m ,

Formula used:

  T=2πlg    .......(1)

Here, T is the time period of the pendulum, l is the length of the pendulum and g is the acceleration due to gravity.

Calculation:

The PE or potential energy is maximum at the top point of the swing.

Conclusion:

Hence, potential difference will take maximum values.

(e)

To determine

The point at which the KE is minimum.

(e)

Expert Solution
Check Mark

Explanation of Solution

Given:

The length of the rope, l=10 m ,

Formula used:

  T=2πlg    .......(1)

Here, T is the time period of the pendulum, l is the length of the pendulum and g is the acceleration due to gravity.

Calculation:

The KE or kinetic energy is minimum at the top point of the swing.

Conclusion:

Hence, the required answer are given above.

(f)

To determine

The point at which the potential energy is minimum.

(f)

Expert Solution
Check Mark

Explanation of Solution

Given:

The length of the rope, l=10 m ,

Formula used:

  T=2πlg    .......(1)

Here, T is the time period of the pendulum, l is the length of the pendulum and g is the acceleration due to gravity.

Calculation:

The PE or potential energy is minimum at the bottom point of the swing.

Conclusion:

Hence, the potential energy will take minimum value.

Chapter 14 Solutions

Glencoe Physics: Principles and Problems, Student Edition

Ch. 14.1 - Prob. 11SSCCh. 14.1 - Prob. 12SSCCh. 14.1 - Prob. 13SSCCh. 14.1 - Prob. 14SSCCh. 14.2 - Prob. 15PPCh. 14.2 - Prob. 16PPCh. 14.2 - Prob. 17PPCh. 14.2 - Prob. 18PPCh. 14.2 - Prob. 19PPCh. 14.2 - Prob. 20PPCh. 14.2 - Prob. 21PPCh. 14.2 - Prob. 22PPCh. 14.2 - Prob. 23PPCh. 14.2 - Prob. 24PPCh. 14.2 - Prob. 25PPCh. 14.2 - Prob. 26SSCCh. 14.2 - Prob. 27SSCCh. 14.2 - Prob. 28SSCCh. 14.2 - Prob. 29SSCCh. 14.2 - Prob. 30SSCCh. 14.3 - Prob. 31SSCCh. 14.3 - Prob. 32SSCCh. 14.3 - Prob. 33SSCCh. 14.3 - Prob. 34SSCCh. 14 - Prob. 36ACh. 14 - Prob. 37ACh. 14 - Prob. 38ACh. 14 - Prob. 39ACh. 14 - Prob. 40ACh. 14 - Prob. 41ACh. 14 - Prob. 42ACh. 14 - Prob. 43ACh. 14 - Prob. 44ACh. 14 - Prob. 45ACh. 14 - Prob. 46ACh. 14 - Prob. 47ACh. 14 - Prob. 48ACh. 14 - Prob. 49ACh. 14 - Prob. 50ACh. 14 - Prob. 51ACh. 14 - Prob. 52ACh. 14 - Prob. 53ACh. 14 - Prob. 54ACh. 14 - Prob. 55ACh. 14 - Prob. 56ACh. 14 - Prob. 57ACh. 14 - Prob. 58ACh. 14 - Prob. 59ACh. 14 - Prob. 60ACh. 14 - Prob. 61ACh. 14 - Prob. 62ACh. 14 - Prob. 63ACh. 14 - Prob. 64ACh. 14 - Prob. 65ACh. 14 - Prob. 66ACh. 14 - Prob. 67ACh. 14 - Prob. 68ACh. 14 - Prob. 69ACh. 14 - Prob. 70ACh. 14 - Prob. 71ACh. 14 - Prob. 72ACh. 14 - Prob. 73ACh. 14 - Prob. 74ACh. 14 - Prob. 75ACh. 14 - Prob. 76ACh. 14 - Prob. 77ACh. 14 - Prob. 78ACh. 14 - Prob. 79ACh. 14 - Prob. 80ACh. 14 - Prob. 81ACh. 14 - Prob. 82ACh. 14 - Prob. 83ACh. 14 - Prob. 84ACh. 14 - Prob. 85ACh. 14 - Prob. 86ACh. 14 - Prob. 87ACh. 14 - Prob. 88ACh. 14 - Prob. 89ACh. 14 - Prob. 90ACh. 14 - Prob. 91ACh. 14 - Prob. 92ACh. 14 - Prob. 93ACh. 14 - Prob. 94ACh. 14 - Prob. 95ACh. 14 - Prob. 96ACh. 14 - Prob. 97ACh. 14 - Prob. 98ACh. 14 - Prob. 99ACh. 14 - Prob. 100ACh. 14 - Prob. 101ACh. 14 - Prob. 102ACh. 14 - Prob. 103ACh. 14 - Prob. 104ACh. 14 - Prob. 105ACh. 14 - Prob. 106ACh. 14 - Prob. 107ACh. 14 - Prob. 1STPCh. 14 - Prob. 2STPCh. 14 - Prob. 3STPCh. 14 - Prob. 4STPCh. 14 - Prob. 5STPCh. 14 - Prob. 6STPCh. 14 - Prob. 7STPCh. 14 - Prob. 8STPCh. 14 - Prob. 9STPCh. 14 - Prob. 10STPCh. 14 - Prob. 11STP

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