Chapter 14.1, Problem 1PP

To determine

The spring constant.

Answer to Problem 1PP

  $2.0\times 10²N/m$

Explanation of Solution

Given information:

Spring stretches $=12cm$

Weight of object $=24N$

Formula used:

This is general formula for force of a spring.

  $F=-kx$ ,

Where,

  $F=$ force.

  $k=$ spring constant

Calculation:

  $\begin{array}{c}\text{12}\text{cm}\text{=}\frac{\text{12}}{\text{100}}\text{m}\\ \text{=}\text{0}\text{.12}\text{m}\end{array}$

Here, $x=-0.12\text{N/m}$

  $F$

  $=24N$

After put the values in formula

  $\begin{array}{l}F=-kx\\ \Rightarrow k=-\frac{F}{x}\end{array}$

Now, put the values

  $k=-\frac{F}{x}$

  $\begin{array}{l}=\frac{-24N}{-0.12m}\\ =200N/m\end{array}$

or $2.0\times 10²N/m$

Conclusion:

Thus, the spring constant is $200N/m$ .