Chapter 14.3, Problem 22PP

To determine

The final size of the balloon.

Answer to Problem 22PP

The final size of the balloon is $1.74\text{L}$ .

Explanation of Solution

Given info:

Room temperature, $T_1=20°\text{C}=\left(20°\text{C}+273\right)\text{K}=293\text{K}$

Refrigerator temperature is, $T_2=-18°\text{C}=\left(-18°\text{C}+273\right)\text{K}=255\text{K}$

Initial size of the balloon, $V_1=2\text{L}$

Formula Used:

Write the expression to calculate the final size of the balloon using Charles’s law.

  $V_2=\frac{T_2{V}_1}{T_1}$

Where,

• The final size of the balloon is $V_2$ .

Calculation:

Substitute all the values in the above expression.

  $\begin{array}{c}{V}_2=\frac{\left(255\text{K}\right)\left(2\text{L}\right)}{293\text{K}}\\ =1.74\text{L}\end{array}$

Conclusion:

Thus, the final size of the balloon is $1.74\text{L}$ .