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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

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BuyFindarrow_forward

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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. Pennies in the United States consist of a zinc core that is electroplated with a thin coating of copper. Zinc dissolves in hydrochloric acid, hut copper does not. If a small scratch is made on the surface of a penny, it is possible to dissolve away the zinc core, leaving only the thin shell of copper. Identify which element is oxidized and which is reduced in the reaction for the dissolving of the zinc by the acid.

Zn ( s ) + 2 HCl ( a q ) ZnCl 2 ( a q ) + H 2 ( g )

Interpretation Introduction

Interpretation:

The element being oxidized and reduced in the given reaction should be determined.

Concept Introduction:

The oxidation state is defined as the charge(s) that an atom would have when electron(s) were transferred completely from a molecule or ion.

The element being oxidized is the one whose oxidation increases in the reaction whereas the reduced element is the one whose oxidation number decreases in the reaction.

Explanation

Given:

Zns + 2HClaq  ZnCl2s+H2(g)

The oxidation state is defined as the charge(s) that an atom would have when electron(s) were transferred completely from a molecule or ion.

While determining the oxidation state of compound, the element with greater electronegativity is assigned with negative value of oxidation state which is equal to the charge as an anion in ionic compounds and element whose oxidation states are fixed are assigned. For compounds with no charge, the sum of oxidation states is zero.

The oxidation states are determined as:

Since, Zn and H2 are in its stable elemental state so; the oxidation state of each is zero for HCl and ZnCl2 the oxidation is determined as:

For HCl:

The oxidation state of Cl is assigned as -1 and the oxidation state of H is assigned as x:

Since, HCl has no charge so; the sum of oxidation state must be zero

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