   # Perform the following conversions between the English and metric systems: a . 358 m to ft b . 10 .0 km to mi c . 1 .55 m to in . d . 23 cm to in . ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

#### Solutions

Chapter
Section ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 2, Problem 27E
Textbook Problem
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## Perform the following conversions between the English and metric systems: a . 358 m to ft b . 10 .0 km to mi c . 1 .55 m to in . d . 23 cm to in .

Interpretation Introduction

Interpretation:

Each of the given conversions of English system to metric system and vice versa is to be performed.

Concept Introduction:

Dimensional analysis is useful in converting one unit to another.

To convert a quantity au1 from one unit to another, that is, u1u2, first write a conversion factor u2u1, then multiply the conversion factor with the given quantity au1, cancelling units to get the quantity in the desired unit as follows:

au1×u2u1=au2

### Explanation of Solution

a) 358 m to ft.

To convert m to ft, first write the correct conversion factor by using the following relationship:

1 m=39.37 in.1 ft=12 in.

Thus, correct conversion factors will be (39.37 in.1 m)and(1 ft12 in.).

Multiply the conversion factors with the given quantity, cancelling units to get the desired quantity.

Hence,

358 m×39.37in.1m×1 ft12in.=1.17×103 ft

b) 10.0 km to mi.

To convert km to mi, first write the correct conversion factor by using the following relationship:

1 km=0.6214 mi

Thus, correct conversion factor will be (0.6214 mi1 km).

Multiply the conversion factor with the given quantity, cancelling units to get the desired quantity.

Hence,

10.0 km×0

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