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Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

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Section
BuyFindarrow_forward

Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 2, Problem 19E
Textbook Problem
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The circumference of Earth at the equator is 40,075 km. Convert this distance into each of the following units:

a. meters

b. miles

c. feet

Interpretation Introduction

Interpretation:

The distance given in km unit is to be converted to meters, miles and feet.

Concept introduction:

Dimensional analysis is useful in converting from one unit to another.

To convert a quantity au1 from one unit to another, that is, u1u2, first write a conversion factor u2u1 then multiply the conversion factor with the given quantity au1, cancelling units to get the quantity in the desired unit as follows;

au1×u2u1=au2

Explanation of Solution

a) Meters

To convert kilometer to meter, first write the correct conversion factor by using the following relationship:

1 km=103 m

Thus, the correct conversion factor will be (103 m1km).

Multiply the conversion factor with the given quantity, cancelling units to get the desired quantity as follows:

40075 km×103 m1 km=4.0075×107 m

b) Miles

To convert kilometer to miles, first write the correct conversion factor by using the following relationship:

1 km=0.6214 mi

Thus, the correct conversion factor will be (0.6214 mi1km).

Multiply the conversion factor with the given quantity, cancelling units to get the desired quantity as follows:

40075 km×0.6214 mi1 km=2.4902×104 mi

c) Feet

To convert kilometer to feet, first convert kilometer to miles and write the correct conversion factor by using the following relationship:

1 km=0

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Chemistry In Focus
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