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Interpretation:
The existence of enantiomeric forms of the given compound is to be explained.
Concept introduction:
The molecules that are nonsuperimposable or not identical with their mirror images are known as chiral molecules.
A pair of two mirror images that are nonidentical is known as enantiomers, which are optically active.
The objects or molecules that are superimposable with their mirror images are achiral objects or molecules and these objects have a centre of symmetry or plane of symmetry.
The achiral compounds in which plane of symmetry is present internally and consists of chiral centres are known as meso compounds but they are optically inactive.
The stereoisomers that are nonsuperimposable on each other and not mirror images of each other are known as diastereomers.
Chiral molecules are capable of rotating plane polarized light
The molecules that are superimposable or identical with their mirror images are known as achiral molecules, and achiral molecules are not capable of rotating the plane-polarised light.
Enantiomers are pairs of compounds that are nonsuperimposable mirror images of each other.
The compounds having a plane of symmetry do not exhibit enantiomeric forms.
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Chapter 21 Solutions
Organic Chemistry
- In some nucleophilic substitutions under SN1 conditions, complete racemization does not occur and a small excess of one enantiomer is present. For example, treatment of optically pure 1-bromo-1-phenylpropane with water forms 1-phenyl-1-propanol. (a) Calculate how much of each enantiomer is present using the given optical rotation data. (b) Which product predominates-the product of inversion or the product of retention of configuration? (c) Suggest an explanation for this phenomenon. H Br он H20 1-bromo-1-phenylpropane 1-phenyl-1-propanol observed [a) = +5.0 optically pure S isomer, [a] =-48 %3Darrow_forwardIn some nucleophilic substitutions under SN1 conditions, complete racemization does not occur and a small excess of one enantiomer is present. For example, treatment of optically pure 1-bromo-1-phenylpropane with water forms 1-phenylpropan-1-ol. (a) Calculate how much of each enantiomer is present using the given optical rotation data. (b) Which product predominates—the product of inversion or the product of retention of configuration? (c) Suggest an explanation for this phenomenon.arrow_forwardConsider the E2 elimination of Compound A, and answer the following questions: (a) Label each stereocenter in Compound A with the correct R or S configuration. (b) Draw the structures of the major product with correct stereochemistry. Assume D and H have the same reactivity.arrow_forward
- 5-Hydroxyhexanal forms a six-membered cyclic hemiacetal, which predominates at equilibrium in aqueous solution. (a) Draw a structural formula for this cyclic hemiacetal. (b) How many stereoisomers are possible for 5-hydroxyhexanal? (c) How many stereoisomers are possible for this cyclic hemiacetal? (d) Draw alternative chair conformations for each stereoisomer and label groups axial or Also predict which of the alternative chair conformations for each stereoisomer is more stable.arrow_forward(a) Which diastereomer of oct-4-ene yields a mixture of two enantiomers, (4R,5R)- and (4S, 5S)-4,5-dibromooctane on reaction with Br2? (b) Which diastereomer of oct-4-ene yields a single meso compound, (4R, 5S)-4,5-dibromooctane?arrow_forwardThe compound 3,4-dimethyl-hexan-3-ol of 3R, 4S configuration is treated with a concentrated HBr solution at room temperature. A mixture of two stereoisomers is obtained.If the reaction mixture above is heated, the appearance of several other compounds is observed. 1) Draw the different compounds obtained using the wedge-flywheel representation. 2) What is the majority product? Explain 3) Propose a modification of the experimental conditions in order to obtain the exclusive formation of these compounds obtained after heatingarrow_forward
- The compounds drawn should each contain a cyclohexane ring. For all three compounds draw a wedge and dash structure, Chair I, and Chair II conformations. Formula: C9H18 with substitution 1,1- disubstituted with stereochemistry of (R,S) Formula: C7H13Cl with substitution 1,3- disubstituted with stereochemistry of (R,R) Formula: C7H14O with substitution 1,4- disubstituted with stereochemistry (S,S)arrow_forwardDehydrohalogenation of 1-chloro-1-methylcyclopropane affords two alkenes (A and B) as products. Explain why A is the major product despite the fact that it contains the less substituted double bond.arrow_forwardDraw the structure of an alkyl bromide with molecular formula CgH13Br that fits each description: (a) a 1° alkyl bromide with one stereogenic center; (b) a 2° alkyl bromide with two stereogenic centers; (c) an achiral 3° alkyl bromide.arrow_forward
- In some nucleophilic substitutions under SN1 conditions, complete racemization does not occur and a small excess of one enantiomer is present. For example, treatment of optically pure 1-bromo-1-phenylpropane with water forms 1- phenylpropan-1-ol. (a) Calculate how much of each enantiomer is present using the given optical rotation data. (b) Whichproduct predominates—the product of inversion or the product of retention of conguration? (c) Suggest an explanation for this phenomenon.arrow_forwardHexahelicene seems a poor candidate for optical activity because all its carbon atomsare sp2hybrids and presumably flat. Nevertheless, hexahelicene has been synthesized and separated into enantiomers. Its optical rotation is enormous: [a]D = 3700°.Explain why hexahelicene is optically active, and speculate as to why the rotation isso largearrow_forwardWhen (S)-2-bromobutane undergoes an SN2 reaction with CH3O-, the product is the compound shown below. What is/are the configuration(s) of the product(s) obtained from this reaction? O equal mixture of R and S H₂C a mixture of enantiomers with more R than S S only CH3 CH OR only O a mixture of enantiomers with more S than R H₂ CH₂arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
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