   Chapter 22.7, Problem 3.4ACP

Chapter
Section
Textbook Problem

Cerium(IV) oxide is used in catalytic converters for the oxidation of CO (to give cerium(III) oxide and CO2). The cerium(III) oxide is converted back to cerium(IV) oxide by atmospheric oxygen. Balance equations for these reactions.

Interpretation Introduction

Interpretation:

Balanced equation for the given compound has to be written.

Concept introduction:

The law of conservation of mass states that no atoms can be created or destroyed in a chemical reaction, therefore, the number of atoms present in the reactants is equal to the number of atoms present in the products.

Balanced reaction is a chemical reaction in which number of atoms for each element in the reaction and the total charge are same on both reactant side and the product side.

Steps in balancing the information

• Step 1: Write the unbalanced equation
• Step 2: Find the coeffienct to balance the equation.
• The coeffienct should be reduced to the smallest whole number
Explanation

(a)

The given compound is cerium (IV) oxide is reaction with carbon monoxide to give cerium (III) oxide and carbon dioxide.

CeO2(s)+CO(g)Ce2O3(s)+CO2(g)

Balance the equation is given below,

Balance the cerium atom in the given equation, when balancing the equation, we should not alter the subscripts and we can change coefficients.

There is one cerium atom in the left side and two cerium atoms in the right side. Therefore two molecule of cerium (IV) oxide is added to left side of reaction. Therefore the balanced equation is given below.

2CeO2(s)+CO(g)Ce2O3(s)+ CO2(g)

cerium (III) oxide is reaction with oxygen to give cerium (IV) oxide

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