Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
Question
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Chapter 23, Problem 99A
Interpretation Introduction

Interpretation:

The number of moles of ATP a human body can produce from sugar in a bushel of medium sized red delicious apple is to be calculated.

Concept introduction:

Molecular mass of a compound is the molar mass of atoms of every atom in the compound. The formula to calculate moles is,

Moles=MassMolarmass

Expert Solution & Answer
Check Mark

Answer to Problem 99A

The number of moles of ATP a human body can produce from sugar in a bushel of medium sized red delicious apple is 3.384 mol.

Explanation of Solution

A medium sized apple contains 17.0 g of glucose. Molecular formula of glucose is C6H12O6. First the molecular mass of glucose is to be calculated.

Molecular mass of C6H12O6=6×12.0g/mol+12×1.00g/mol+6×16.0g/mol=72.0g/mol+12g/mol+96g/mol=180g/mol

Now, the mass of glucose is to be multiplied with a suitable conversion factor to calculate moles of glucose present in medium sized apple.

Molesofglucose=MassofglucoseMolarMassofglucose=17g180gmol1=0.094mol

A human body produces 36 moles of ATP from 1 mole of sugar. So, moles of ATP in 0.094 mol is,

MolesofATP=0.094 molglucose×36molesof ATP1mol glucose=3.384molesof ATP

Hence, mole of ATP produced from red medium sized apple is 3.384 mol.

Conclusion

From a medium sized apple, human body can produce 3.384 moles of ATP.

Chapter 23 Solutions

Chemistry: Matter and Change

Ch. 23.2 - Prob. 11SSCCh. 23.3 - Prob. 12SSCCh. 23.3 - Prob. 13SSCCh. 23.3 - Prob. 14SSCCh. 23.3 - Prob. 15SSCCh. 23.3 - Prob. 16SSCCh. 23.3 - Prob. 17SSCCh. 23.3 - Prob. 18SSCCh. 23.3 - Prob. 19SSCCh. 23.4 - Prob. 20SSCCh. 23.4 - Prob. 21SSCCh. 23.4 - Prob. 22SSCCh. 23.4 - Prob. 23SSCCh. 23.4 - Prob. 24SSCCh. 23.4 - Prob. 25SSCCh. 23.5 - Prob. 26SSCCh. 23.5 - Prob. 27SSCCh. 23.5 - Prob. 28SSCCh. 23.5 - Prob. 29SSCCh. 23.5 - Prob. 30SSCCh. 23.5 - Prob. 31SSCCh. 23.5 - Prob. 32SSCCh. 23 - Prob. 33ACh. 23 - Prob. 34ACh. 23 - Prob. 35ACh. 23 - Prob. 36ACh. 23 - Prob. 37ACh. 23 - Prob. 38ACh. 23 - Prob. 39ACh. 23 - Prob. 40ACh. 23 - Prob. 41ACh. 23 - Prob. 42ACh. 23 - Prob. 43ACh. 23 - Prob. 44ACh. 23 - Prob. 45ACh. 23 - Prob. 46ACh. 23 - Prob. 47ACh. 23 - Prob. 48ACh. 23 - Prob. 49ACh. 23 - Prob. 50ACh. 23 - Prob. 51ACh. 23 - Prob. 52ACh. 23 - Prob. 53ACh. 23 - Prob. 54ACh. 23 - Prob. 55ACh. 23 - Prob. 56ACh. 23 - Prob. 57ACh. 23 - Prob. 58ACh. 23 - Prob. 59ACh. 23 - Prob. 60ACh. 23 - Prob. 61ACh. 23 - Prob. 62ACh. 23 - Prob. 63ACh. 23 - Prob. 64ACh. 23 - Prob. 65ACh. 23 - Prob. 66ACh. 23 - Prob. 67ACh. 23 - Prob. 68ACh. 23 - Prob. 69ACh. 23 - Prob. 70ACh. 23 - Prob. 71ACh. 23 - Prob. 72ACh. 23 - Prob. 73ACh. 23 - Prob. 74ACh. 23 - Prob. 75ACh. 23 - Prob. 76ACh. 23 - Prob. 77ACh. 23 - Prob. 78ACh. 23 - Prob. 79ACh. 23 - Prob. 80ACh. 23 - Prob. 81ACh. 23 - Prob. 82ACh. 23 - Prob. 83ACh. 23 - Prob. 84ACh. 23 - Prob. 85ACh. 23 - Prob. 86ACh. 23 - Prob. 87ACh. 23 - Prob. 88ACh. 23 - Prob. 89ACh. 23 - Prob. 90ACh. 23 - Prob. 91ACh. 23 - Prob. 92ACh. 23 - Prob. 93ACh. 23 - Prob. 94ACh. 23 - Prob. 95ACh. 23 - Prob. 96ACh. 23 - Prob. 97ACh. 23 - Prob. 98ACh. 23 - Prob. 99ACh. 23 - Prob. 100ACh. 23 - Prob. 101ACh. 23 - Prob. 102ACh. 23 - Prob. 104ACh. 23 - Prob. 105ACh. 23 - Prob. 106ACh. 23 - Prob. 1STPCh. 23 - Prob. 2STPCh. 23 - Prob. 3STPCh. 23 - Prob. 4STPCh. 23 - Prob. 5STPCh. 23 - Prob. 6STPCh. 23 - Prob. 7STPCh. 23 - Prob. 8STPCh. 23 - Prob. 9STPCh. 23 - Prob. 10STPCh. 23 - Prob. 11STPCh. 23 - Prob. 12STPCh. 23 - Prob. 13STPCh. 23 - Prob. 14STPCh. 23 - Prob. 15STPCh. 23 - Prob. 16STPCh. 23 - Prob. 17STP
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