The curved arrows for the given reaction are to be drawn. Concept introduction: The entropy term in a Diels-Alder reaction is negative because the reaction decreases the number of independent molecules (i.e., the reaction leads to less “disorder”). This means that increasing the temperature makes ΔG o rxn less negative (because ΔG o rxn = ΔH o rxn - TΔS ° rxn ). Under normal conditions, the prototypical Diels-Alder has a substantially negative change in standard free energy, giving it a very large equilibrium constant. As a result, the reaction is irreversible.

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Answer 1

Question

Chapter 24, Problem 24.13YT

Interpretation Introduction

Interpretation:

The curved arrows for the given reaction are to be drawn.

Concept introduction:

The entropy term in a Diels-Alder reaction is negative because the reaction decreases the number of independent molecules (i.e., the reaction leads to less “disorder”). This means that increasing the temperature makes ΔGorxn less negative (because ΔGorxn= ΔHorxn-TΔS°rxn). Under normal conditions, the prototypical Diels-Alder has a substantially negative change in standard free energy, giving it a very large equilibrium constant. As a result, the reaction is irreversible.

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Answer 2

Question

Chapter 24, Problem 24.13YT

Interpretation Introduction

Interpretation:

The curved arrows for the given reaction are to be drawn.

Concept introduction:

The entropy term in a Diels-Alder reaction is negative because the reaction decreases the number of independent molecules (i.e., the reaction leads to less “disorder”). This means that increasing the temperature makes ΔGorxn less negative (because ΔGorxn= ΔHorxn-TΔS°rxn). Under normal conditions, the prototypical Diels-Alder has a substantially negative change in standard free energy, giving it a very large equilibrium constant. As a result, the reaction is irreversible.

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Answer 3

Question

Chapter 24, Problem 24.13YT

Interpretation Introduction

Interpretation:

The curved arrows for the given reaction are to be drawn.

Concept introduction:

The entropy term in a Diels-Alder reaction is negative because the reaction decreases the number of independent molecules (i.e., the reaction leads to less “disorder”). This means that increasing the temperature makes ΔGorxn less negative (because ΔGorxn= ΔHorxn-TΔS°rxn). Under normal conditions, the prototypical Diels-Alder has a substantially negative change in standard free energy, giving it a very large equilibrium constant. As a result, the reaction is irreversible.

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Answer 4

Question

Chapter 24, Problem 24.13YT

Interpretation Introduction

Interpretation:

The curved arrows for the given reaction are to be drawn.

Concept introduction:

The entropy term in a Diels-Alder reaction is negative because the reaction decreases the number of independent molecules (i.e., the reaction leads to less “disorder”). This means that increasing the temperature makes ΔGorxn less negative (because ΔGorxn= ΔHorxn-TΔS°rxn). Under normal conditions, the prototypical Diels-Alder has a substantially negative change in standard free energy, giving it a very large equilibrium constant. As a result, the reaction is irreversible.

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Answer 5

Chapter 24, Problem 24.13YT

Interpretation Introduction

Interpretation:

The curved arrows for the given reaction are to be drawn.

Concept introduction:

The entropy term in a Diels-Alder reaction is negative because the reaction decreases the number of independent molecules (i.e., the reaction leads to less “disorder”). This means that increasing the temperature makes ΔGorxn less negative (because ΔGorxn= ΔHorxn-TΔS°rxn). Under normal conditions, the prototypical Diels-Alder has a substantially negative change in standard free energy, giving it a very large equilibrium constant. As a result, the reaction is irreversible.

Answer 6

Chapter 24, Problem 24.13YT

Interpretation Introduction

Interpretation:

The curved arrows for the given reaction are to be drawn.

Concept introduction:

The entropy term in a Diels-Alder reaction is negative because the reaction decreases the number of independent molecules (i.e., the reaction leads to less “disorder”). This means that increasing the temperature makes ΔGorxn less negative (because ΔGorxn= ΔHorxn-TΔS°rxn). Under normal conditions, the prototypical Diels-Alder has a substantially negative change in standard free energy, giving it a very large equilibrium constant. As a result, the reaction is irreversible.

Answer 7

Chapter 24, Problem 24.13YT

Interpretation Introduction

Interpretation:

The curved arrows for the given reaction are to be drawn.

Concept introduction:

The entropy term in a Diels-Alder reaction is negative because the reaction decreases the number of independent molecules (i.e., the reaction leads to less “disorder”). This means that increasing the temperature makes ΔGorxn less negative (because ΔGorxn= ΔHorxn-TΔS°rxn). Under normal conditions, the prototypical Diels-Alder has a substantially negative change in standard free energy, giving it a very large equilibrium constant. As a result, the reaction is irreversible.

Answer 8

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Answer 11

Ch. 24 - Prob. 24.1P Ch. 24 - Prob. 24.2P Ch. 24 - Prob. 24.3P Ch. 24 - Prob. 24.4P Ch. 24 - Prob. 24.5P Ch. 24 - Prob. 24.6P Ch. 24 - Prob. 24.7P Ch. 24 - Prob. 24.8P Ch. 24 - Prob. 24.9P Ch. 24 - Prob. 24.10P

Solution Summary: The author explains that the entropy term in a Diels-Alder reaction is negative because the reaction decreases the number of independent molecules.

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Chapter 24 Solutions