   Chapter 24, Problem 34GQ

Chapter
Section
Textbook Problem

The first step of the metabolic process known as glycolysis is the conversion of glucose to glucose- 6-phosphate. This process has a positive value for∆rGₒ'Glucose + Pi → Glucose-6-phosphate + H2O∆rGₒ' = +13.8 kJ/mol-rxnThis reaction is coupled to the hydrolysis of ATPATP + H2O → ADP + Pi     ∆rGₒ' = -30.5 kJ/mol-rxnWhat is the sum of these two equations and the value of ∆rGₒ' for the coupled reaction? Is the coupled reaction product-favored at equilibrium?

Interpretation Introduction

Interpretation:

The sum of free energy of a coupled reaction and to check the coupled reaction favored at equilibrium has to found.

Concept introduction: In coupled reaction spontaneous reaction is directly coupled with non-spontaneous reaction. For spontaneous reaction Gibbs free energy is negative and for non-spontaneous reaction Gibbs free energy is positive.

By adding together ,these coupled reaction give an overall reactions, and the ΔG of this reaction will be the sum of ΔG value spontaneous and non-spontaneous reaction (individual reactions).

Explanation

Glucose + Piglucose 6 phosphate + H2O   ΔG°'= +13.8 kJmol1                       (1)

ATP + H2OADP + Pi ΔG°' = -30.5kJ.mol-1                                                        (2)

Add the reaction (1) and (2) together (water term cancel out).

glucose + ATPglucose 6 phosphate + ADP  ΔG°'= -16

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