(a) Interpretation: The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦,2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined. Concept introduction: Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation. 1â—¦ orPrimary C atom = C atom which is bonded with one another C atom 2â—¦ orSecondary C atom= C atom which is bonded with two other C atoms 3â—¦ orTertiary C atom= C atom which is bonded with three other C atoms 4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Question

Want to see the full answer?

Answer 1

Question

Chapter 26, Problem 92IAE

Interpretation Introduction

(a)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦,2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ orPrimary C atom = C atom which is bonded with one another C atom

2â—¦ orSecondary C atom= C atom which is bonded with two other C atoms

3â—¦ orTertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Interpretation Introduction

(b)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦, 2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ or Primary C atom = C atom which is bonded with one another C atom

2â—¦ or Secondary C atom= C atom which is bonded with two other C atoms

3â—¦ or Tertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Interpretation Introduction

(c)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦, 2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ or Primary C atom = C atom which is bonded with one another C atom

2â—¦ or Secondary C atom= C atom which is bonded with two other C atoms

3â—¦ or Tertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

2,4-dimethy/-2,3-pentadiene has the following line diagram structure (with hydrogens drawn in). Explain with PICTURES of the sigma and pi bonds and with words why this molecule does not actually have a planar arrangement of methyl groups. Include an electron diagram of the hybridization of the central carbon atom.

what is the molecular geometry of cyclopropane and the hybridization ?

Identify the hybridization and bond angles at the carbon atoms in the molecule shown:

Answer 2

Question

Chapter 26, Problem 92IAE

Interpretation Introduction

(a)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦,2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ orPrimary C atom = C atom which is bonded with one another C atom

2â—¦ orSecondary C atom= C atom which is bonded with two other C atoms

3â—¦ orTertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Interpretation Introduction

(b)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦, 2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ or Primary C atom = C atom which is bonded with one another C atom

2â—¦ or Secondary C atom= C atom which is bonded with two other C atoms

3â—¦ or Tertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Interpretation Introduction

(c)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦, 2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ or Primary C atom = C atom which is bonded with one another C atom

2â—¦ or Secondary C atom= C atom which is bonded with two other C atoms

3â—¦ or Tertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 26, Problem 92IAE

Interpretation Introduction

(a)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦,2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ orPrimary C atom = C atom which is bonded with one another C atom

2â—¦ orSecondary C atom= C atom which is bonded with two other C atoms

3â—¦ orTertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Interpretation Introduction

(b)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦, 2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ or Primary C atom = C atom which is bonded with one another C atom

2â—¦ or Secondary C atom= C atom which is bonded with two other C atoms

3â—¦ or Tertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Interpretation Introduction

(c)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦, 2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ or Primary C atom = C atom which is bonded with one another C atom

2â—¦ or Secondary C atom= C atom which is bonded with two other C atoms

3â—¦ or Tertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 26, Problem 92IAE

Interpretation Introduction

(a)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦,2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ orPrimary C atom = C atom which is bonded with one another C atom

2â—¦ orSecondary C atom= C atom which is bonded with two other C atoms

3â—¦ orTertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Interpretation Introduction

(b)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦, 2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ or Primary C atom = C atom which is bonded with one another C atom

2â—¦ or Secondary C atom= C atom which is bonded with two other C atoms

3â—¦ or Tertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Interpretation Introduction

(c)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦, 2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ or Primary C atom = C atom which is bonded with one another C atom

2â—¦ or Secondary C atom= C atom which is bonded with two other C atoms

3â—¦ or Tertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 26, Problem 92IAE

Interpretation Introduction

(a)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦,2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ orPrimary C atom = C atom which is bonded with one another C atom

2â—¦ orSecondary C atom= C atom which is bonded with two other C atoms

3â—¦ orTertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Interpretation Introduction

(b)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦, 2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ or Primary C atom = C atom which is bonded with one another C atom

2â—¦ or Secondary C atom= C atom which is bonded with two other C atoms

3â—¦ or Tertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Interpretation Introduction

(c)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦, 2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ or Primary C atom = C atom which is bonded with one another C atom

2â—¦ or Secondary C atom= C atom which is bonded with two other C atoms

3â—¦ or Tertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Answer 6

Chapter 26, Problem 92IAE

Interpretation Introduction

(a)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦,2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ orPrimary C atom = C atom which is bonded with one another C atom

2â—¦ orSecondary C atom= C atom which is bonded with two other C atoms

3â—¦ orTertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Answer 7

Chapter 26, Problem 92IAE

Interpretation Introduction

(a)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦,2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ orPrimary C atom = C atom which is bonded with one another C atom

2â—¦ orSecondary C atom= C atom which is bonded with two other C atoms

3â—¦ orTertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Answer 8

Interpretation Introduction

(b)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦, 2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ or Primary C atom = C atom which is bonded with one another C atom

2â—¦ or Secondary C atom= C atom which is bonded with two other C atoms

3â—¦ or Tertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Answer 9

Interpretation Introduction

(b)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦, 2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ or Primary C atom = C atom which is bonded with one another C atom

2â—¦ or Secondary C atom= C atom which is bonded with two other C atoms

3â—¦ or Tertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Answer 10

Interpretation Introduction

(c)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦, 2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ or Primary C atom = C atom which is bonded with one another C atom

2â—¦ or Secondary C atom= C atom which is bonded with two other C atoms

3â—¦ or Tertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Answer 11

Interpretation Introduction

(c)

Interpretation:

The hybridization of carbon atom, total C-C σ bonds and π bonds with 1â—¦, 2â—¦,3â—¦ and 4â—¦ carbon atoms should be determined.

Concept introduction:

Hybridization is the process of mixing of atomic orbitals to form same energy and same shape hybrid orbitals which form covalent bond with overlapping of atomic orbitals of other atoms. The number of chemical bonds formed by the atom always determine type of hybridization. Sigma bonds could only form by hybrid orbitals whereas pi bonds are always formed by overlapping of un-hybrid orbitals hence hybridization is not part of pi bond formation.

1â—¦ or Primary C atom = C atom which is bonded with one another C atom

2â—¦ or Secondary C atom= C atom which is bonded with two other C atoms

3â—¦ or Tertiary C atom= C atom which is bonded with three other C atoms

4â—¦ or Quaternary C atom= C atom which is bonded with four other C atoms

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 15

Ch. 26 - Prob. 1E Ch. 26 - Draw a structural formula for each of the...Ch. 26 - Prob. 3E Ch. 26 - Write structural formulas corresponding to these...Ch. 26 - Prob. 5E Ch. 26 - Prob. 6E Ch. 26 - Prob. 7E Ch. 26 - Prob. 8E Ch. 26 - What is the relationship, if any, between the...Ch. 26 - Prob. 10E

Solution Summary: The author explains that the number of chemical bonds formed by the atom determines the type of hybridization.

Concept explainers

Want to see the full answer?

Chapter 26 Solutions