Biochemistry
6th Edition
ISBN: 9781305577206
Author: Reginald H. Garrett, Charles M. Grisham
Publisher: Cengage Learning
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Chapter 29, Problem 13P
Interpretation Introduction
Interpretation:
The length of the DNA segment in the B-form DNA needs to be determined. The fraction of a DNA turns around the core octamer comprises of 50 bp of DNA needs to be calculated. The 50 bp of DNA should be compared to the typical size of eukaryotic promoter modules and response elements needs to be explained.
Concept introduction:
In a solution, the common persistence length is 46−50 nm or 140−150 base pairs (the diameter of
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Eukaryotic life also uses chromatin modifications to turn transcripts on and off. We talked about PARP-1 and its ability to remodel chromatin in response to what?
Histones form more accessible chromatin because of
Select one:
a. Reduced electrostatic attraction between the histone and the negatively charged DNA backbone
b. Increased electrostatic attraction between the histone and the negatively charged DNA backbone
c. Reduced covalent bonding between the histone and the negatively charged DNA backbone
d. Increased covalent bonding between the histone and the negatively charged DNA backbone
Define the following terms:a. histonesb. heterochromatinc. euchromatind. intergenic sequencese. tandem repeats
Chapter 29 Solutions
Biochemistry
Ch. 29 - Prob. 1PCh. 29 - The Events in Transcription Initiation Describe...Ch. 29 - Substrate Binding by RNA Polymerase RNA polymerase...Ch. 29 - Comparison of Prokaryotic and Eukaryotic...Ch. 29 - Prob. 5PCh. 29 - Prob. 6PCh. 29 - Prob. 7PCh. 29 - Alternative Splicing Possibilities Suppose exon 17...Ch. 29 - Prob. 9PCh. 29 - Prob. 10P
Ch. 29 - Post-transcriptional Modification of Eukaryotic...Ch. 29 - Prob. 12PCh. 29 - Prob. 13PCh. 29 - The Lariat Intermediate in RNA Splicing Draw the...Ch. 29 - Prob. 15PCh. 29 - Prob. 16PCh. 29 - Prob. 17PCh. 29 - Prob. 18PCh. 29 - Figure 29.15 highlights in red the DNA phosphate...Ch. 29 - Chromatin decompaction is a preliminary step in...
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- An article entitled “Nucleosome Positioning at the Replication Fork” states: “both the ‘old’ randomly segregated nucleosomes as well as the ‘new’ assembled histone octamers rapidly position themselves (within seconds) on the newly replicated DNA strands” [Lucchini et al. (2002)]. Given this statement, how would one compare the distribution of nucleosomes and DNA in newly replicated chromatin? How could one experimentally test the distribution of nucleosomes on newly replicated chromosomes?arrow_forwardduring anaphase of animal cells, describe the appearance of the DNA, spindle fibers and location of the chromosomes pls do not copy from googlearrow_forwardWhat would happen in the directionality of that activity were reversed? Would proofreading work? If the genomic DNA polymerase were missing its proofreading function (deletion in the domain or subunit), what phenotype would you expect to see in those cells? Please give me the correct answer quickly I will give you upvotearrow_forward
- true or false 1.) The unique stem-loop structures of the transfer RNA helps the RNA perform its function of joining ribosomal proteins to form the sites for protein synthesis. 2.) DNA molecules can perform their function in replication and transcription as long as the 2 strands remain intact and not separated. 3.) Histone proteins are able to associate with DNA segments because of the anionic nature of the amino acids arg and lys. 4.) The long solenoid structure of the chromatin material binds to a protein scaffold and folds further to form the chromatin/chromosome structure. 5.) Primary amines and keto groups of the nitrogen bases are involved in base-pairing in double stranded DNA.arrow_forwardHistones and DNA polymerase subunits are both synthesized in the cytosol but they function in the nucleus: histones in packaging DNA and the polymerase in replicating DNA. How are they imported into the nucleus? Compare the import process for histones to that for DNA polymerase subunits.arrow_forwardTrue or False? Chromatin remodeling involves addition or removal of chemical groups to histones, which alters its binding affinity to DNA and influences whether the promoter region is available for RNApol to bind.arrow_forward
- How does the CREB protein contribute to chromatin remodeling? Question 6 options: Inhibits HDAC via phosphorylation Activates HDAC via phosphorylation Inhibits HDAC via methylation Activates HDAC via acetylationarrow_forwardBriefly describe three ways that ATP-dependent chromatin-remodeling complexes may change chromatin structure.arrow_forwardNucleosomes are the ball-like structures around which the double helix winds. What proteins make up nucleosomes? Group of answer choices hertone histone heterochromatin euchromatinarrow_forward
- Kree DNA has histone like proteins that wrap up in nucleosomes. The Kree have a core DNA length of 255 bp and a linker DNA of 45 bp. The Kree genome is made up of approximately 6x108 base pairs of DNA. Determine the number of nucleosomes in each nucleus.arrow_forwardWhich of the following statements are correct about telomeres (select all that apply)? A. A total of 6 nucleotides are lost at the end of each chromsome during each replication cycle. B. Addition of telomerase to cells that have undergone breakage-fusion-bridge cycles can reverse crisis C. Shortening of telomeres prevents cells from becoming cancerous even if they have oncogenes and defective tumor suppressor genes D. All cancer cells express high levels of telomerase E. Chromosomes without telomeres tend to undergo end-to-end fusionsarrow_forwardSome retrotransposons and retroviruses integrate preferentially into regions of the chromosome that are packaged in euchromatin. Why might these mobile genetic elements have evolved this strategy?arrow_forward
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