Biochemistry
6th Edition
ISBN: 9781305577206
Author: Reginald H. Garrett, Charles M. Grisham
Publisher: Cengage Learning
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Chapter 29, Problem 15P
Interpretation Introduction
Interpretation:
The length of
Concept introduction:
In biology, deoxyribonucleic acid (
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pppApCpCpUpApGpApU-OH(a) Using the straight-chain sugar convention, write the structure of the DNA strand that encoded this short stretch of RNA.(b) Using the simplest convention for representing the DNA base sequence, write the structure of the nontemplate DNA strand.
Composition as a mole fraction of one of a double-stranded DNA strand
T = 0.22 and C = 0.30. In the light of this information, the following values are
Calculate as a fraction. If the given information is used to calculate the desired value,
If it is not sufficient, indicate the result as X.
Replication:- what other enzymes are involved in the initiation phase?- explain the role of primers in this phase- how is the building of the leading strand different from that of the lagging strand?
Chapter 29 Solutions
Biochemistry
Ch. 29 - Prob. 1PCh. 29 - The Events in Transcription Initiation Describe...Ch. 29 - Substrate Binding by RNA Polymerase RNA polymerase...Ch. 29 - Comparison of Prokaryotic and Eukaryotic...Ch. 29 - Prob. 5PCh. 29 - Prob. 6PCh. 29 - Prob. 7PCh. 29 - Alternative Splicing Possibilities Suppose exon 17...Ch. 29 - Prob. 9PCh. 29 - Prob. 10P
Ch. 29 - Post-transcriptional Modification of Eukaryotic...Ch. 29 - Prob. 12PCh. 29 - Prob. 13PCh. 29 - The Lariat Intermediate in RNA Splicing Draw the...Ch. 29 - Prob. 15PCh. 29 - Prob. 16PCh. 29 - Prob. 17PCh. 29 - Prob. 18PCh. 29 - Figure 29.15 highlights in red the DNA phosphate...Ch. 29 - Chromatin decompaction is a preliminary step in...
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- Number of Okazaki Fragments in E. coli and Human DNA Replication Approximately how many Okazaki fragments are synthesized in the course of replicating an E. coli chromosome? How many in replicating an “average� human chromosome?arrow_forwardHelicase Unwinding of the E. coli Chromosome Hexameric helicases, such as DnaB, the MCM proteins, and papilloma virus El helicase (illustrated in Figures 16.22 to 16.25), unwind DNA by passing one strand of the DNA duplex through the central pore, using a mechanism based on ATP-dependent binding interactions with the bases of that strand. The genome of E. coli K12 consists of 4,686,137 nucleotides. Assuming that DnaB functions like papilloma virus El helicase, from the information given in Chapter 16 on ATP-coupled DNA unwinding, calculate how many molecules of ATP would be needed to completely unwind the E. coli K 12 chromosome.arrow_forwardCodon-Anticodon Recognition: Base-Pairing Possibilities (Integrates with Chapter 11.) Draw base-pair structures for (a) a G:C base pair. (b) a C:G base pair. (C) a G:U base pair, and (d) a U:G base pair. Note how these various base pairs differ in the potential hydrogen-bonding patterns they present within the major groove and minor groove of a double-helical nucleic acid.arrow_forward
- Functional Consequences of Y-Family DNA Polymerase Structure The eukaryotic translesion DNA polymerases fall into the Y family of DNA polymerases. Structural studies reveal that their fingers and thumb domains are small and stubby (see Figure 28.10). In addition, Y-family polymerase active sites are more open and less constrained where base pairing leads to selection of a dNTP substrate for the polymerase reaction. Discuss the relevance of these structural differences. Would you expect Y-family polymerases to have 3-exonuclease activity? Explain your answer.arrow_forwardCOMPLEMENTARY DNA SEQUENCE OF GACGGCTTAAGATGCarrow_forward22-71 Indicate whether each of the following statementsinvolving differences between DNA and RNA moleculesis true or false.a. Base pairing occurs in DNA but not in RNA.b. Both DNA and RNA are double-stranded molecules.c. RNA molecules are much larger than DNAmolecules.d. The base T in DNA is replaced by the base A in RNAarrow_forward
- 41. Define the relationship between twist, writhe and linking number. Are the twist and writhe topological properties or geometric properties? Why is this significant? What is the twist and writhe of relaxed (but not broken) circular DNA?arrow_forward23. Contrast the “functional” size of the four major classes of biomolecules. Background: Up until now, we have (generally) been considering the ideal properties of biomolecules without regard to the relative sizes of these molecules. In general, a “functional” DNA molecule is orders of magnitude larger than any other biomolecule. A typical size single-domain protein is, however, on the order of a very small segment of DNA. If we are going to understand the physiological role of DNA we need to consider the physiochemical implications of the size of a “functional” DNA molecule. About 30x bigger"arrow_forwardINSTRUCTION: Given the DNA sequence below, provide the answers to the following items. a. complimentary DNA strand 1.) G A A A T G A C C A G A T T T A T G G C C T G A 2). A T G C G A C C T T A A G T C A A T T G C G A C b. mRNA 1.) G A A A T G A C C A G A T T T A T G G C C T G A 2). A T G C G A C C T T A A G T C A A T T G C G A C c. protein synthesized 1.) G A A A T G A C C A G A T T T A T G G C C T G A 2). A T G C G A C C T T A A G T C A A T T G C G A Carrow_forward
- Describe the d=features of the following DNA-binding domains and how they interact with DNA. Helix-turn-Helix Zinc Finger Leucine Zipper Helix-loop-Helixarrow_forwardCompare the DNA binding modes of minor groove binding, intercalating, and crosslinking agents and explain how these interactions give rise to specific pharmaceutical applications. Use the molecular structures of at least one DNA PLEASE DISCUSS THIS IN DETAIL! and correct answers only ! will give good rating! thank you.arrow_forwardZ-DNA derives its name from the zig-zag conformation of phosphate groups. What features of the DNA molecule allow this structure to form?arrow_forward
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