Biochemistry
6th Edition
ISBN: 9781305577206
Author: Reginald H. Garrett, Charles M. Grisham
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 29, Problem 17P
Interpretation Introduction
Interpretation:
To determine the reason for the position of a-amanitin to be consistent with its inhibition modes.
Concept introduction:
DNA or Deoxyribonucleic acid is a molecule made of two chains which coil around one another. These form a double helix which carries instructions genetical in nature like related to reproduction, growth, development, functioning of the living organisms.
a-amanitin inhibits RNA polymerase II. This toxin which slows the polymerase translocation along DNA for NTP substrates has no effect on enzyme’s affinity.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
The RNA polymerase from bacteriophage T7 diff ers structurally from prokaryotic and eukaryotic RNAPs and is extremely specifi c for its own promoter. Why do these properties make T7 RNAP useful in experiments with recombinant DNA?
Trinucleotide repeat expansions (TNREs) are associated with severaldifferent human inherited diseases. Certain types of TNREsproduce a long stretch of the amino acid glutamine within theencoded protein. When a TNRE exerts its detrimental effect byproducing a glutamine stretch, are the following statements true orfalse?A. The TNRE is within the coding sequence of the gene.B. The TNRE prevents RNA polymerase from transcribing thegene properly.C. The trinucleotide sequence is CAG.D. The trinucleotide sequence is CCG.
Regulation of Genes and Their products
1. Given the following genotypes, explain how the mutation (identified by a (-) superscript) wil affect E. coll grown in lactose medium. Will the lac operon be on or off? Will there be a complete set of gene products from the lac operon? What will be the implication of the missing gene product, if ever? Will the cell be able to survive in the lactose medium or not?
a. I+p+o+z- y+
b. i- p+o+z+y+
c. i+p+o- z+y+
d. i+p- o+z+y+
2. In terms of the trp operon, differentiate between two normal bacterial cultures, one grown in a medium supplied with tryptophan and the other medium without tryptophan.
3. Experiments show that mutations at gene E lead to non-repressible transcription of trp genes. Why?
Chapter 29 Solutions
Biochemistry
Ch. 29 - Prob. 1PCh. 29 - The Events in Transcription Initiation Describe...Ch. 29 - Substrate Binding by RNA Polymerase RNA polymerase...Ch. 29 - Comparison of Prokaryotic and Eukaryotic...Ch. 29 - Prob. 5PCh. 29 - Prob. 6PCh. 29 - Prob. 7PCh. 29 - Alternative Splicing Possibilities Suppose exon 17...Ch. 29 - Prob. 9PCh. 29 - Prob. 10P
Ch. 29 - Post-transcriptional Modification of Eukaryotic...Ch. 29 - Prob. 12PCh. 29 - Prob. 13PCh. 29 - The Lariat Intermediate in RNA Splicing Draw the...Ch. 29 - Prob. 15PCh. 29 - Prob. 16PCh. 29 - Prob. 17PCh. 29 - Prob. 18PCh. 29 - Figure 29.15 highlights in red the DNA phosphate...Ch. 29 - Chromatin decompaction is a preliminary step in...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biochemistry and related others by exploring similar questions and additional content below.Similar questions
- Functional Consequences of Y-Family DNA Polymerase Structure The eukaryotic translesion DNA polymerases fall into the Y family of DNA polymerases. Structural studies reveal that their fingers and thumb domains are small and stubby (see Figure 28.10). In addition, Y-family polymerase active sites are more open and less constrained where base pairing leads to selection of a dNTP substrate for the polymerase reaction. Discuss the relevance of these structural differences. Would you expect Y-family polymerases to have 3-exonuclease activity? Explain your answer.arrow_forwardHeteroduplex DNA Formation in Recombination From the information in Figures 28.17 and 28.18, diagram the recombinational event leading to the formation of a heteroduplex DNA region within a bacteriophage chromosome.arrow_forwardThe Enzymatic Activities of DNA Polymerase I (a) What are the respective roles of the 5 -exonudease and 3 -exonuclease activities of DNA polymerase I? (b) What might be a feature of an E. coli strain that lacked DNA polymerase I 3 -exonuclease activity?arrow_forward
- 88Sequential binding of RNA polymerase II-TFIIF complex, TFIIE, and TFIIH completes ___________________ formation. A.pre-initiation complexb.TF recognition elementc.pre-elongation complexD.TATA binding complex 89Which of the following is the GDP-GTP exchange protein?A.EF-Tub.none of the abovec.EF-TsD.EF-G 90RNA polymerase II has 14 subunits. Yesornoarrow_forwardNumber of Okazaki Fragments in E. coli and Human DNA Replication Approximately how many Okazaki fragments are synthesized in the course of replicating an E. coli chromosome? How many in replicating an “average� human chromosome?arrow_forwardMultiple Replication Forks in E. coli II On the basis of Figure 28.2, draw a simple diagram illustrating replication of the circular E. coli chromosome (a) at an early stage, (b) when one-third completed, (c) when two-thirds completed, and (d) when almost finished, assuming the initiation of replication at oriC has occurred only once. Then, draw a diagram showing the E. coli chromosome in problem 3 where the E. coli cell is dividing every 20 minutes.arrow_forward
- Substrate Binding by RNA Polymerase RNA polymerase has t binding sites for ribonucleoside triphosphates: the initiation site and the elongation site. The initiation site has a greater Km for NTPs than the elongation site. Suggest what possible significance this fact might have for the control of transcription in cells.arrow_forwardMolecules of DNA Polymerase III per Cell vs. Growth Rate It is estimated that there are 40 molecules of DNA polymerase III per E. coli cell, is it likely that the growth rate of E. coli is limited by DNA polymerase III availability?arrow_forwardAlternative Splicing Possibilities Suppose exon 17 were deleted from the fast skeletal muscle troponin T gene (Figure 29.46). How many different mRNAs could now be generated by alternative splicing? Suppose that exon 7 in a wild-type troponin T gene were duplicated. How many different mRNAs might be generated from a transcript of this new gene by alternative splicing?arrow_forward
- Chemical Mutagenesis of DNA Bases Show the nucleotide sequence changes that might arise in a dsDNA (coding strand segment GCTA) upon mutagenesis with (a) HNO2, (b) bromouracil, and (C) 2-aminopurine.arrow_forwardSemiconservative or Conservative DNA Replication If 15N-Iabeled E. coli DNA has a density of 1.724 g/mL, 14N-labeled DNA has a density of 1.710 g/mL, and E. coli cells grown for many generations on 14NH4+as a nitrogen source are transferred to media containing 15NH4+as the sole N-source, (a) What will be the density of the DNA after one generation, assuming replication is semiconservative? (b) Suppose replication took place by a conservative mechanism in which the parental strands remained together and the two progeny strands were paired. Design an experiment that could distinguish between semiconservative and conservative modes of replication.arrow_forwardpppApCpCpUpApGpApU-OH(a) Using the straight-chain sugar convention, write the structure of the DNA strand that encoded this short stretch of RNA.(b) Using the simplest convention for representing the DNA base sequence, write the structure of the nontemplate DNA strand.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- BiochemistryBiochemistryISBN:9781305577206Author:Reginald H. Garrett, Charles M. GrishamPublisher:Cengage Learning
Biochemistry
Biochemistry
ISBN:9781305577206
Author:Reginald H. Garrett, Charles M. Grisham
Publisher:Cengage Learning
DNA vs RNA (Updated); Author: Amoeba Sisters;https://www.youtube.com/watch?v=JQByjprj_mA;License: Standard youtube license